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LekaFEV [45]
3 years ago
15

The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in

this glass strikes the glass–air interface at a 25.50∘ angle of incidence and refracts out into the air. What is the angular separation between the red and violet components of the spectrum that emerges from the glass?
Physics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

10.16 degrees

Explanation:

Apply Snells Law for both wavelenghts

\(n_{1}sin\theta_{1} = n_{2}sin\theta_{2}\)

For red

(1.620)(sin 25.5) = (1)(sin r)

For red, the angle is 35.45degrees

For violet

(1.660)(sin 25.5) = (1)(sin v)

For violet, the angle is 45.6 degrees

The difference is 45.6- 35.45 = 10.16 degrees

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What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a
Montano1993 [528]

Answer:

   f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

speed of sound = 331 m/s

By Doppler's effect

f' = (\dfrac{v}{v-v_s}})f

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

f' = \dfrac{341}{341-24.7}}\times 3400

   f' = 1.078 x 3400

   f' = 3665.51 Hz

The frequency received by the stationary mouse is equal to 3665.51 Hz

6 0
3 years ago
Why did earth most likely form into distinct, separate layers? (HELP ASAP PLZ)
g100num [7]

Answer:

C

Explanation:

Rocks with hotter temperatures sank to the bottom of the Earth. The rocks with the hottest temperature became the core and the rocks with the least amount of heat became the crust.

Hope this helps!

8 0
3 years ago
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What force is the total force felt by an object?
skelet666 [1.2K]

Answer:

net force

Explanation:

Net force felt by an object.

6 0
3 years ago
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A biconvex lens is formed by using a piece of plastic(n=1.70).
creativ13 [48]

Answer:

f =17.15\ cm

Explanation:

given,

refractive index of lens, n = 1.70

Radius of curvature of front surface. R₁ = 20 cm

Radius of curvature of the back surface, R₂ = 30 cm

focal length= ?

\dfrac{1}{f}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})

    R₁ = +20 cm

    R₂ = -30 cm

    n = 1.70

\dfrac{1}{f}=(1.70-1)(\dfrac{1}{20}-\dfrac{1}{-30})

\dfrac{1}{f}=0.70 \times 0.0833

f = \dfrac{1}{0.7 \times 0.0833}

f =17.15\ cm

the focal length of the lens is equal to 17.15 cm

3 0
3 years ago
A rock is thrown upward with a velocity of 22 meters per second from the top of a 25 meter high cliff, and it misses the cliff o
Mice21 [21]

Answer:

The rock will reach 9 m from the ground at eaxactly 5.06 s after it was initially thrown upwards.

Explanation:

We will use the equations of motion for this.

u = initial velocity of the rock = 22 m/s

g = acceleration due to gravity = -9.8 m/s²

y = vertical position of the rock at a time t = 9 m

y₀ = initial height of the rock = 25 m

t = time it takes for the rock to reach height of 9 m.

(y-y₀) = ut + 0.5gt²

(9 - 25) = 22t + 0.5(-9.8)t²

- 14 = 22t - 4.9t²

4.9t² - 22t - 14 = 0

solving this quadratic equation,

t = 5.055 s or - 0.565 s

Since time cannot be negative,

t = 5.055 s = 5.06 s

Hope this Helps!!!

6 0
3 years ago
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