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Yuri [45]
3 years ago
14

How long will it take for the car to accelerate

Physics
1 answer:
solniwko [45]3 years ago
8 0
You have to be 90 m away from the cat

Just divide 90 by 17.4 and you will get - 5.172 seconds

- It will take 5.17 seconds to accelerate uniformly to stop in exactly 2 m before the cat
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Consider a system of a cliff diver and the earth. the gravitational potential energy of the system decreases by 28,000 j as the
olga2289 [7]

The decrease in gravitational potential energy of the system is given by

\Delta U = (mg) \Delta h

where

m is the mass, g is the gravitational acceleration, and \Delta h is the variation of height of the system.


(mg) also corresponds to the weight of the diver, therefore if we rearrange the equation and we use \Delta U=28000 J and \Delta h=32.0 m, we can find her weight:

mg=\frac{\Delta U}{\Delta h}=\frac{28000 J}{32 m}=875 N

5 0
3 years ago
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3 years ago
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Lilit [14]
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8 0
3 years ago
A 750-kg automobile is moving at 16.8 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
anygoal [31]

Answer:h=19.4 m

Explanation:

Given

mass of automobile m=750\ kg

Initial height of automobile h_o=5\ m

Velocity at this instant v=16.8\ m/s

If the car stops somewhere at a height h

Thus conserving total energy we get

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2+mgh_o=\frac{1}{2}m(0)^2+mgh

\frac{v^2}{2g}+h_o=h

h=5+\frac{16.8^}{2\times 9.8}

h=5+14.4

h=19.4\ m

6 0
3 years ago
a motorcycle accelerates from 15 m/s to 20 m/s over a distance of 50 meters. what is its average acceleration?
devlian [24]
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s² So the average acceleration is 1.75 m/s²
5 0
3 years ago
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