<span>In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.</span>
Answer:
They are the same element.
Explanation:
Atom >>>>> Proton >>>> Neutron
A >>>>>>>> 8 >>>>>>>>> 10
B >>>>>>>> 8 >>>>>>>>> 12
From the table above we can see that both atoms have the same proton number.
Therefore, they are the same element because they have the same proton number which means that they have the same atomic number. The element in this case is existing as an isotope in that the atoms have the same proton number but different neutron number.
The distance traveled by the hockey player is 0.025 m.
<h3>The principle of conservation of linear momentum;</h3>
- The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.
The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;
![m_1v_1 = m_2 v_2\\\\v_1 = \frac{m_2 v_2}{m_1} \\\\v_1 = \frac{0.150 \times 45}{90} \\\\v_1 = 0.075 \ m/s](https://tex.z-dn.net/?f=m_1v_1%20%3D%20m_2%20v_2%5C%5C%5C%5Cv_1%20%3D%20%5Cfrac%7Bm_2%20v_2%7D%7Bm_1%7D%20%5C%5C%5C%5Cv_1%20%3D%20%5Cfrac%7B0.150%20%5Ctimes%2045%7D%7B90%7D%20%5C%5C%5C%5Cv_1%20%3D%200.075%20%5C%20m%2Fs)
The time taken for the puck to reach 15 m is calculated as follows;
![t = \frac{d}{v} \\\\t = \frac{15\ m}{45 \ m/s} \\\\t = 0.33 \ s](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bd%7D%7Bv%7D%20%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B15%5C%20m%7D%7B45%20%5C%20m%2Fs%7D%20%5C%5C%5C%5Ct%20%3D%200.33%20%5C%20s)
The distance traveled by the hockey player at the calculated time is;
![d = vt\\\\d = 0.075 \ m/s \ \times 0.33 \ s\\\\d = 0.025 \ m](https://tex.z-dn.net/?f=d%20%3D%20vt%5C%5C%5C%5Cd%20%3D%200.075%20%5C%20m%2Fs%20%5C%20%5Ctimes%200.33%20%5C%20s%5C%5C%5C%5Cd%20%3D%200.025%20%5C%20m)
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
19.6N
Explanation:
Given parameters:
Mass of rock = 2kg
Speed = 30m/s
Unknown:
Net force on the rock = ?
Solution:
The net force acting on this rock is a function of the acceleration due to gravity acting upon it.
Net force = weight = mass x acceleration due to gravity
Net force = 2 x 9.8 = 19.6N downward
Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding