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Elodia [21]
2 years ago
13

PLEASE LOOK AT MY RECENT QUESTIONS THERE ALL IN MATHAMATICS. I NEED HELP WITH THEM ASAP!

Mathematics
1 answer:
sineoko [7]2 years ago
8 0

Answer:

ok I can help post again fast with in 3min

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The weight of an African elephant is 6 × 106 grams; the weight of a tiger is 3 × 105 grams. How many times heavier is the elepha
likoan [24]
2 grams

6 x 106 = 636
3 x 105 = 315

315 x (2) = about 630
3 0
3 years ago
Read 2 more answers
Which equation represents the statement: Three times the sum of a number and 5 is –30?
castortr0y [4]

Answer:

3(n+5)=-30

Step-by-step explanation:

Three times the sum of a number and 5 is - 30

Vocabulary:

times = multiplication, represented with *

sum = addition, represented by +

unknown number = n

Three * the sum of a number and 5

The sum of a number and 5 is the same as saying n + 5

So we are multiplying 3 by n + 5

Because n is an unknown variable we have to separate the sum of n and 5 from being multiplied by 3 with parenthesis. We do this because if we want to multiply 3 by the sum of n and 5. If we put 3 * n + 5 we are only multiplying the unknown variable by 3 not including the 5 that is added to it.

So we get 3( n + 5 ) is -30

3(n+5)=-30 is the answer.

3 0
2 years ago
Read 2 more answers
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
Gradient from 2 - 1/2y = 0​
kirill115 [55]

Given :

  1. 2 - 1/2y = 0

To find :-

  • The gradient form .

Solution :-

<u>The </u><u>gradient</u><u> form</u><u>/</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u>

  • y = mx + c ,

<u>On </u><u>converting</u><u> </u><u>,</u>

  • 2 - 1/2y = 0
  • 1/2y = 2
  • y = 2*2
  • y = 4
  • y = 0x + 4
4 0
2 years ago
Brandon follows a 2,800 calorie per day diet. He has 11 servings of breads and cereal, which average 140 calorie each. Yesterday
JulijaS [17]
Breads/cereals;

11 * 140 = 1540 calories

Fruits/vegetables;

9 * 60 = 540 calories

Meat/milk;

x * 180 = 2800 - (1540 + 540)

180x = 2800 - 2080

180x = 720

x = 4 servings
8 0
3 years ago
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