Answer:
-62.5008
Step-by-step explanation:
the pattern here is dividing by -5, so just continue dividing by -5 starting on -3 and continuing 4 more times. record each number and then add them together using a calculator. you will get -62.5008
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Joint Frequency because of the fact that it "joins" one number from the column(up and down) and one from the row(side-by-side), hence the two-way table.
Answer:
8 red marbles.
Step-by-step explanation:
All together we have 40 marbles. The fraction of marbles that are red is 1/5 which means that we should divide the total number of marbles, which is 40 by the denominator ( Bottom number of fraction ) 5 so that we get the number of groups that have 1 red marble in them. In this case we have 8 groups.
40/5=8
You always divide by the denominator ( Bottom number of fraction ) first and then you multiply your answer by the numerator ( Top number of fraction ) .
If each group has 1 red marble in it and we have 8 groups, it means that we have 8 red marbles in the bag.
1 * 8 = 8 red marbles in the bag
If the numerator (number above the fraction line) was more than one, then this would mean that we have more than 1 marble in each group of marbles.
Example:
If we had 3/5 we would have 3 marbles in each group of marbles. This means that instead of doing 1 * 8 we would have to do 3 * 8 = 24. We would have 24 red marbles in the bag.
Easy and quick way if you do not need the explanation:
Another way we could do this is by simply multiplying the fraction ( 1/5 ) by the total number of marbles ( 40 ). This would still give us an answer of 8 red marbles in the bag. 40/5=8, 8*1=8
Given that figure A with radius of 2 inches is dilated to form figure B, the radius of B will be given by:
Radius B=(radius A)×(scale factor)
but
scale factor=4
thus
Radius of B will be:
2×4
=8 inches
Answer:
0
Step-by-step explanation:
Hi! We are given the limit expression:
If we directly substitute x = 2 then we get 0/0 which is an indeterminate form. Therefore, we need to find other methods to evaluate the limit that does not become an indeterminate form.
As for rational function with square root in it, we conjugate the expression by multiplying both denominator and numerator with the square root expression.
When two same square root expressions multiply each other, the square root is taken out as shown above.
From denominator, we can factor x²-4 to (x-2)(x+2) via differences of two squares.
Hence:
Cancel x-2.
Then substitute x = 2 which we receive 0/4 = 0.
Henceforth, the limit value of expression is 0.
