The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3
The meaning of observations to see small touch
I believe the answer is: in order not to write very big or very small number values
1.2 moles of (nph4)3po3 is.......159.6 grams
Their boiling points tend to increase with chain length.<span>
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