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ryzh [129]
3 years ago
13

What is the break down of food into energy

Chemistry
1 answer:
AnnyKZ [126]3 years ago
3 0

it is nutrients that's it


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Either C or D. Those r the answers that make more sense.
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Why is U-235 the most common nuclear fuel instead of the more abundant U-238? State a clear topic sentence and support it with e
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<h3><u>Answer and explanation</u>;</h3>
  • <em><u>The isotope U-235 is an important common nuclear fuel because under certain conditions it can readily be split, yielding a lot of energy. It is therefore said to be 'fissile' and use the expression 'nuclear fission'.</u></em>
  • <em><u>Uranium 238 on the other hand is not fissionable by thermal neutrons, but it can undergo fission from fast or high energy neutrons. Hence it is not fissile, but it is fissionable.</u></em>
  • In a nuclear power station fissioning of uranium atoms replaces the burning of coal or gas.  Heat created by splitting the U-235 atoms is then used to make steam which spins a turbine to drive a generator, producing electricity.
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3 years ago
HNO3 + KOH + H2O + KNO3<br><br> ACID:<br> BASE:<br> SALT:
SSSSS [86.1K]

Explanation:

acid, HNO3

base, KOH

salt ,KNO3

4 0
3 years ago
A large cyclotron directs a beam of He++ nuclei onto a target with a beam current of 0.250 mA. (a) How many He++ nuclei per seco
nikitadnepr [17]

Answer:

a. 7.8*10¹⁴ He⁺⁺ nuclei/s

b. 4000s

c. 7.7*10⁸s

Explanation:

I = 0.250mA = 2.5 * 10⁻³A

Q = 1.0C

1 e- contains 1.60 * 10⁻¹⁹C

But He⁺⁺ Carrie's 2 charge = 2 * 1.60*10⁻¹⁹C = 3.20*10⁻¹⁹C

(A).

No. Of charge per second = current passing through / charge

1 He⁺⁺ = 2.50 * 10⁻⁴ / 3.2*10⁻¹⁹C

1 He⁺⁺ = 7.8 * 10¹⁴ He⁺⁺ nuclei

(B).

I = Q / t

From this equation, we can determine the time it takes to transfer 1.0C

I = 1.0 / 2.5*10⁻⁴ = 4000s

(C).

Time it takes for 1 mol of He⁺⁺ to strike the target =?

Using Avogadro's ratio,

1.0 mole of He = (6.02 * 10²³ ions/mol ) * (1 / 7.81*10¹⁴ He ions)

Note : ions cancel out leaving the value of the answer in mols.

1.0 mol of He = 7.7 * 10⁸s

8 0
3 years ago
A chemist determined by measurements that 0.030 moles of barium participated in a chemical reaction. Calculate the mass of bariu
schepotkina [342]

Answer: 4.1 g of barium precipitated.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}

Given : moles of barium = 0.030

Molar mass of barium = 137 g/mol

0.030=\frac{x}{137}

x= 4.1 g

Thus there are 4.1 g of barium that precipitated.

3 0
3 years ago
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