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Tems11 [23]
3 years ago
5

Find the area of the figure

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0
The answer is going to be 15
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Which of the following terminating decimals is equivalent to -1 3/4<br> ?
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It would be - 1.75. Hope it helps! :)
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What is 48 square feet in square meters
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Step-by-step explanation: 1 Square foot (sqft) is equal to 0.09290304 square meter (sqm). For example, to convert 100 square feet to square meters, multiply 100 by 0.09290304, that makes 9.290304 sqm is 100 sqft. Hope this helps.

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2 years ago
Plz I need help on #12
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Step-by-step explanation:

7 0
3 years ago
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Which values for h and k are used to write the function f of x = x squared 12 x 6 in vertex form?
Nesterboy [21]

The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

<h3>How to rewrite in vertex form?</h3>

The equation is given as:

f(x) = x^2 + 12x + 6

Rewrite as:

x^2 + 12x + 6 = 0

Subtract 6 from both sides

x^2 + 12x = -6

Take the coefficient of x

k = 12

Divide by 2

k/2 = 6

Square both sides

(k/2)^2 = 36

Add 36 to both sides of x^2 + 12x = -6

x^2 + 12x + 36= -6 + 36

Evaluate the sum

x^2 + 12x + 36= 30

Express as perfect square

(x + 6)^2 = 30

Subtract 30 from both sides

(x + 6)^2 -30 = 0

So, the equation f(x) = x^2 + 12x + 6 becomes

f(x) = (x + 6)^2 -30

A quadratic equation in vertex form is represented as:

f(x) = a(x - h)^2 + k

Where:

Vertex = (h,k)

By comparison, we have:

(h,k) = (-6,-30)

Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

3 0
2 years ago
Choose the correct conic section to match the equation. 16x 2 - y 2 = 16 parabola hyperbola ellipse circle
Nastasia [14]

The equation 16x² - y² = 16 represents a hyperbola ⇒ 2nd answer

Step-by-step explanation:

The general form of the equation of a conic is

Ax² + Bxy + Cy² + Dx + Ey + F = 0, where A, B, C, D, E, and F

are constants

To find the type of conic that the equation represent find B² - 4AC

1. B² - 4AC < 0 and the conic is exist, then it's ellipse or circle,

   if A = C, (non-zero) then it is a circle, if A ≠ C, then it is an ellipse

2. B² - 4AC = 0 and the conic is exist, then it's a parabola

3. B² - 4AC > 0 and the conic is exist, then it's a hyperbola

∵ The equation is 16x² - y² = 16

- Subtract 16 from both sides

∴ 16x² - y² - 16 = 0

∵ Ax² + Bxy + Cy² + Dx + Ey + F = 0

∴ A = 16 , B = 0 , C = -1 , D = 0 , E = 0 , F = -16

∵ B² - 4AC = (0)² - 4(16)(-1)

∴ B² - 4AC = 64

∵ 64 > 0

∵ B² - 4AC > 0

∴ The conic is hyperbola

The equation 16x² - y² = 16 represents a hyperbola

Learn more:

You can learn more about hyperbola in brainly.com/question/4054269

#LearnwithBrainly

7 0
3 years ago
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