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ICE Princess25 [194]
4 years ago
6

Can I get help with this multiple choice questions (#3) pleasee?

Mathematics
1 answer:
liq [111]4 years ago
5 0
I could tell u it's not 'D' it could be 'A' or 'C', I think it's 'B'
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MrRa [10]
<span>The orthocenter is outside the triangle if it's an obtuse triangle.</span>
7 0
3 years ago
Find the value of x. <br> a) x=109 <br> b) x=115<br> c) x=95<br> d) x=129
NeX [460]

Answer:

A 109

Step-by-step explanation:

Pentagram's angles add up to 540. After subtracting all the other angles, you are left with 109.

3 0
3 years ago
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David has 36 marbles, 24 of which are black and 12 are blue. What is the ratio of black marbles to blue marbles? Write the ratio
iragen [17]
We know there are a total of 36 marbles. We also know 24 out of 36 are black and 12 out of 36 are blue. A ratio is pretty much a division problem... The problem wants the 24 black marbles over the 12 blue marbles. So, 24/12 = 2/1. Now, what this means is that for every 2 black marbles, there is one 1 blue marble. Good luck!
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3 years ago
Enter "1" into cell A1. What do you get for the mean and the MAD of the data set
igor_vitrenko [27]
Ya totally your cool bro
7 0
4 years ago
Expand and simplify (x+5)(x-2)
salantis [7]

Answer:

{x}^{2} - x - 12 = (x + 3)(x - 4)

{x}^{2} + 3x + 2 = (x + 2)(x + 1)

{x}^{2} + 3x - 10 = (x + 5)(x - 2)

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

{x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12

{x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2

{x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10

I am joyous to assist you anytime.

8 0
3 years ago
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