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Phantasy [73]
4 years ago
9

A 112 g hockey puck glides across a frictionless ice surface with no horizontal forces acting on it. If the puck's velocity is 2

2.5 m/s to the right at t = 0 s, what will the puck's horizontal velocity be at t = 225 ms? Round your answer to the nearest 0.1 m/s.
Physics
1 answer:
Burka [1]4 years ago
7 0
22.5 m/s
This is because the puck will not slow down, and maintain a constant velocity.
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A roller coaster is moving at 25m/s at the bottom of a hill. Three seconds later it reaches the top of the hill moving at 10m/s.
marishachu [46]

Answer:

5 m/s^{2}

Explanation:

acceleration is defined as the rate of change of velocity per unit time. Therefore, acceleration, a=\frac {\triangle v}{\triangle t}

where \triangle v is change in velocity and t is time

Substituting initial and final velocities with 25 m/s and 10 m/s then using time as given in the question of 3 s then

a=\frac {25-10}{3}=\frac {15}{3}=5 m/s^{2}

Therefore, the acceleration is 5 m/s^{2}

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Average wavelength of radio waves​
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Answer:

Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km

7 0
3 years ago
Please help, thank you,
Elena-2011 [213]

same, stapler, gravity, motion, acceleration

6 0
3 years ago
Bonds: Including Carbon Compounds Quick Check
Sever21 [200]

Metallic bonds are responsible for many properties of metals, such as conductivity. This is because the bonds can shift because valence electrons are held loosely and move freely. That is option C.

<h3>What are metallic bonds?</h3>

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The characteristics of a metallic compound with metallic bonds include the following:

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5 0
2 years ago
A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north
Sedaia [141]

Answer:

Magnitude of displacement = 2.07 km

Magnitude of average velocity = 1.17 kmph

Explanation:

Let east represent positive x axis and north represent positive y axis.

A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north of west.

1.93 km due wast

           s ₁ = 1.93 i km

1.03 km due south

           s₂ = -1.03 j km

3.84 km in a direction 52.8 ° north of west

           s₃ = -3.84 cos 52.8 i + 3.84 sin 52.8 j = -2.32 i + 3.06 j km

Total displacement

          s = s ₁+  s₂+ s₃ = 1.93 i - 1.03 j -2.32 i + 3.06 j = -0.39 i + 2.03 j

  Magnitude of displacement, =\sqrt{(-0.39)^2+2.03^2}=2.07km

Time taken = 1.771 hour

Magnitude of average velocity, =\frac{2.07}{1.771}=1.17km/hr

7 0
3 years ago
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