The water has an irregular surface so if the light rays fall on top then it will reflect oppositely or in some cases may refract, so the fish will seem a bit smaller or further or closer in anyway, example if u put a straw in water it looks bent but is it ? nope. So the main reason is that it refracts which makes the accuracy lesser which make it difficult.
In a projectile, the horizontal acceleration is zero. The velocity remains constant at all times. However, the <u>vertical acceleration</u> is -9.81m/s^2.
Hope this helps!
Answer and explanation:
The right answer is b) "The excess charge has distributed itself evenly over the outside surface of the sphere".
The hollow metal sphere is a conductor. This means that charges can move freely over its surface. On the other side, a metal body act as an equipotential body. Once some charge is set and there is no voltage differential imprinted over the body, to keep being an equipotential body the charges must distribute evenly on the external surface. Must not exist charge in the volume, or would exist an electrical field and therefore a voltage differential. Also, the charge distribution in the internal surface must be null. If you apply gauss theorem with a gaussian sphere with a radius between the internal and external surface, knowing that field E is null, the enclosed charge must be null.
Answer: 9.375m/s
Explanation: This is an inelastic collision, so the formula is mv1+mv2=(m1+m2)v-final. My work is a follows:
2500kg(12m/s) + 700kg(0m/s)=(2500kg+700kg)(v-final)
30,000kg(m/s)+0=3200kg(v-final)
30,000kg(m/s)/3200kg=9.375m/s
Answer:
a = 1.152s
b = 0.817 m
c = 7.29m/s
Explanation: let the following
From the first equation of linear motion
V = u+at..........1
parameters be represented as :
t = Time taken
v = Final velocity
a = Acceleration due to gravity = 9.8m/s²
u = Initial velocity = 4 m/s
s = Displacement
V = 0
Substitute the values into equation 1
0 = 4-9.8(t)
-4 = -9.8t
t = 4/9.8
t = 0.408s
From : s = ut+1/2at^2.........2
S = 4×0.408+0.5(-9.8)×0.408^2
S= 1.632-4.9(0.166)
S = 1.632-0.815
S = 0.817m
Her highest height above the board is 0.817 m
Total height she would fall is 0.817+1.90 = 2.717 m
From equation 2
s = ut+1/2at^2
2.717 m = 0t+0.5(9.8)t^2
2.717 m = 0+4.9t^2
2.717 m = 4.9t^2
2.717/4.9 = t^2
0.554 =t^2
t =√0.554
t = 0.744s
Hence, her feet were in the air for 0.744+0.408seconds
= 1.152s
Also recall from equation 1
V= u+at
V = 0+9.8(0.744)
V = 7.29m/s
Hence, the velocity when she hits the water is 7.29m/s
Finally,
a = 1.152s
b = 0.817 m
c = 7.29m/s
