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2 years ago

PLS HELP I WILL GIVE BRAINLIEST PLSS

Mathematics

1 answer:

Studentka2010 [4]2 years ago

4 0

Answer:

b IS THE CORRECT ANSWRR!!!

Step-by-step explanation:

HOPE THIS BHELPS

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Change 3/2 to a mixed number

Mariulka [41]

Okay first you have to divide
2 goes into 3
3/2
2 fits into 3 once
1 and the left over is 1 so
1 1/2

4 0

3 years ago

Help me class8 (surds)

Mashcka [7]

Answer:

$\cfrac{991\sqrt{2} }{80}$

Step-by-step explanation:

For a start simplify each of the roots:

$\sqrt{72} =\sqrt{36*2} =6\sqrt{2}$
$\sqrt{50} =\sqrt{25*2} =5\sqrt{2}$
$\sqrt{128} =\sqrt{64*2} =8\sqrt{2}$
$\sqrt{98} =\sqrt{49*2} =7\sqrt{2}$

Now simplify the expression in steps:

$\sqrt{72}-\cfrac{48}{\sqrt{50} } -\cfrac{45}{\sqrt{128} } +2\sqrt{98} =$

$6\sqrt{2}-\cfrac{48}{5\sqrt{2} } -\cfrac{45}{8\sqrt{2} } +2*7\sqrt{2} =$

$6\sqrt{2}-\cfrac{48*8+45*5}{5*8\sqrt{2} } +14\sqrt{2} =$

$20\sqrt{2}-\cfrac{609}{40\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609*\sqrt{2} }{40\sqrt{2} *\sqrt{2} } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{40*2 } =$

$20\sqrt{2}-\cfrac{609\sqrt{2} }{80 } =$

$\sqrt{2} (20-7\cfrac{49}{80} )=$

$\sqrt{2} *12\cfrac{31}{80} =$

$\cfrac{991\sqrt{2} }{80}$

3 0

2 years ago

Pleaseee help if you can!!!!!!!

REY [17]

Answer:

85 degrees

Step-by-step explanation:

Theses angles are the same because its parallell

3 0

2 years ago

What’s the answer for -3(r-4)_>0

Zigmanuir [339]

Answer:

r<4

Step-by-step explanation:

-3(r-4)>0 step 1: distribute the -3

-3r+12>0 explain: -3 times r =-3r, -3 times -4 = 12

next, isolate the -3r by putting 12 on the other side

-3r+12>0 subtract 12 from both sides

-3r>-12 now, divide both sides by -3 (you have to flip the > because you are dividing by a negative) -12 divided by -3 is 4

so you should end up with r<4

8 0

2 years ago

Solve for x. Show your work.<br> 1 x<-12<br> 2

Airida [17]

Answer:

2 is not a solution

Step-by-step explanation:

x < -12

<u>Step 1: Check if 2 is less than -12</u>

2 < -12

No, this doesn't work

Answer: 2 is not a solution

5 0

3 years ago