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igomit [66]
3 years ago
14

If 18 mL of methanol is used to make an aqueous solution that is 15% methanol by volume, how many mL of solution is produced?

Chemistry
1 answer:
Yuri [45]3 years ago
7 0

Answer:

120.0 mL.

Explanation:

  • As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.

We suppose that the initial W% of methanol is 100.0 %

<em>∴ (W%V) before dilution = (W%V) after dilution.</em>

W% before dilution = 100.0 %, V before dilution = 18.0 mL.

W% after dilution = 15.0 %, V after dilution = ??? mL.

<em>∴ V after dilution = (W%V) before dilution/W% after dilution = </em>(100.0 %)(18.0 mL)/(15.0%)<em> = 120.0 mL.</em>

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The K w for water at 0 ∘ C is 0.12 × 10 − 14 . Calculate the pH of a neutral aqueous solution at 0 ∘ C.
dusya [7]

Answer:

pH = 7.46

Explanation:

2H₂O  ⇄  H₃O⁺  .  OH⁻          Kw = [H₃O⁺] . [OH⁻]

[H₃O⁺] = [OH⁻]

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸  M

- log  [H₃O⁺] = pH

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Why does the colour of copper sulphate solution change when an iron nail is dipped in it?
sineoko [7]

Answer:

bcoz iron displaces copper and form the solution iron sulfide

Explanation:

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CuSO4+3Fe---->Fe3SO4+Cu

4 0
4 years ago
Hen a wire carrying a current is wound into a series of loops called coils, each turn of the wire produces a magnetic field. The
Lady_Fox [76]

Answer:

<u><em>Hope it helped </em></u>↓

Explanation:

Electromagnets are basically coils of wire which behave like bar magnets with a distinct north and south pole when an electrical current passes through the coil. The static magnetic field produced by each individual coil loop is summed with its neighbor with the combined magnetic field concentrated like the single wire loop we looked at in the last tutorial in the center of the coil. The resultant static magnetic field with a north pole at one end and a south pole at the other is uniform and a lot more stronger in the center of the coil than around the exterior. So a good question could be "Are electromagnets a magnet that respells, or attracts?" Then find away to explain that question/

(you don't have to do this question it is just a example.)

4 0
3 years ago
Read 2 more answers
If 84.1 g of NaOH and 51.0 g of Al and 25.0 g H20 react which chemical is the limiting reactant?
12345 [234]

Answer:

  • <u><em>H₂O</em></u>

Explanation:

<u>1. Chemical quation</u>

The reaction of aluminium, sodium hydroxide and water is represented by the balanced chemical equation:

  • 2Al(s) + 2NaOH(s) + 6H₂O(l) → 2Na[Al(OH)₄] (aq) + 3H₂(g) ↑

The coefficients of each reactant and product give the theoretical mole ratios.

To find the limiting reactant you compare the theoretical ratios with the ratio of the available substaces.

<u>2. Theoretical mole ratio:</u>

  • 2 mol Al : 2 mol NaOH : 6 mol H₂O

Equivalent to

  • 1 mol Al : 1 mol NaOH : 3 mol H₂O

<u>3. Actual ratio</u>

a) Convert each mass to number of moles

Formula:

  • number of moles = mass in grams / molar mass

Al:

  • molar mass = atomic mass = 26.982g/mol
  • number of moles = 51.0g / 26.982g/mol = 1.89 mol

NaOH:

  • molar mass = 39.997g/mol
  • number of moles = 84.1g / 39.997g/mol = 2.10 mol

H₂O:

  • molar mass = 18.015g/mol
  • number of moles = 25.0g / 18.015g/mol = 1.39 mol

Divide all the mole amounts by the least number:

  • Al: 1.89/1.39 = 1.36
  • NaOH: 2.10 = 1.52
  • H₂O: 1.39 = 1.00

  • 1.36 mol Al : 1.52 mol NaOH : 1.00 mol H₂O

<u>4. Comparison</u>

<u />

Theoretical ratio:

  • 1 mol Al : 1 mol NaOH : 3 mol H₂O

Actual ratio:

  • 1.36 mol Al : 1.52 mol NaOH : 1.00 mol H₂O

     Multiply by 3:

  • 4.08 mol Al : 4.56 mol NaOH : 3.00 mol H₂O

Now, yo can see that the first two are in excess with respect the third one, making that the water consumes first, before any of the other two consumes. Therefore, the limiting reactant is the water.

8 0
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