The mass of the water is 1580 g.
<h3>What is the amount of water formed?</h3>
We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from 7.9 x 10-3 atm to 1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.
Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm
Using;
PV = nRT
n = PV/RT
n = 7.78 * 10^-3 atm * 2.4 x10^5 l/0.082 * (39 + 273)
n = 85 moles
Since 1 mole of carbon dioxide produces 1 mole of water
85 moles of carbon dioxide produces 85 mole of water
Mass of water produced = 85 mole * 18 g/mol
= 1580 g
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Answer:
12 mi/h
Explanation:
Step 1: Given data
Step 2: Convert "d" to miles
We will use the conversion factor 1 mi = 1.60934 km.
6 km × 1 mi/1.60934 km = 3.7 mi
Step 3: Convert "t" to hours
We will use the conversion factor 1 h = 60 min.
19 min × 1 h/60 min = 0.32 h
Step 4: Calculate the average speed of the runner (s)
The speed is equal to the quotient between the total distance and the time elapsed.
s = d/t
s = 3.7 mi/0.32 h = 12 mi/h
Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.
Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
Answer:
H2SO4 ( Sulfuric Acid ) + NaOH ( Sodium Hydroxide ) > Na2SO4 ( Sodium Sulfate ) + H2O ( Water )
Explanation:
