Answer:
440mt/p gallons
Explanation:
We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.
Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:
Area of stripe = width x length
= t inches x m miles (we need to convert both to feet)
= (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)
=440mt square feet
ow we can find out how much paint will be needed by using ratios
p square feet : 1 gallon
440mt square feet : x
x = 440mt/p gallons
Explanation:
Cadmium, nickel, chromium, and silver are sometimes used as protective platings. Metals have a wide range of corrosion resistance. The most active metals (i.e., those that tend to lose electrons easily)--such as magnesium and aluminum--corrode easily and are listed at the top of Table 2-1.
In general chemistry, isotopes are substances that belong to one specific element. So, they all have the same atomic numbers. But they only differ in the mass numbers, or the number of protons and neutrons in the nucleus. In a nutshell, they only differ in the number of neutrons.
For Nickel, there are 5 naturally occurring isotopes. Their identities, masses and relative abundance are listed below
Isotope Abundance Atomic Mass
Ni-58 68.0769% <span>57.9353 amu
Ni-60 </span>26.2231% <span>59.9308 amu
Ni-61 </span>1.1399 % <span>60.9311 amu
Ni-62 </span>3.6345% <span>61.9283 amu
Ni-64 </span>0.9256% <span>63.9280 amu
To determine the average atomic mass of Nickel, the equation would be:
Average atomic mass = </span>∑Abundance×Atomic Mass
Using the equation, the answer would be:
Average atomic mass = 57.9353(68.0769%) + 59.9308(26.2231%) + 60.9311(1.1399%) + 61.9283(3.6345%) + 63.9280(0.9256%)
Average atomic mass = 58.6933 amu
Answer:
metals donate electrons to nonsmetals
