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3 years ago

Which postulate can be used to prove that the triangles are congruent?

Mathematics

1 answer:

Bezzdna [24]3 years ago

7 0

Answer:

D. not congruent

Step-by-step explanation:

Only two pairs of congruent sides are given to us, when we need either 3 pairs of congruent sides (SSS) or two pairs of congruent sides & 1 pair of congruent angles (SAS), or two pairs of congruent angles & one pair of congruent sides (ASA).

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Vinvika [58]

Answer:

{-9,1,11}

Step-by-step explanation:

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3 years ago

Write the additive inverse of 14/113

Helen [10]

Step-by-step explanation:

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3 years ago

Tell if I was right, and I'll thank you and mark you as branliest

PtichkaEL [24]

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3 years ago

Solve the triangle. Round your answers to the nearest tenth. A. m∠A=43, m∠B=55, a=16 B. m∠A=48, m∠B=50, a=23 C. m∠A=48, m∠B=50,

alexgriva [62]

Answer:

D. m∠A=43, m∠B=55, a=20

Step-by-step explanation:

Given:

∆ABC,

m<C = 82°

AB = c = 29

AC = b = 24

Required:

m<A, m<C, and a (BC)

SOLUTION:

Find m<B using the law of sines:

$\frac{sin(B)}{b} = \frac{sin(C)}{c}$

$\frac{sin(B)}{24} = \frac{sin(82)}{29}$

$sin(B)*29 = sin(82)*24$

$\frac{sin(B)*29}{29} = \frac{sin(82)*24}{29}$

$sin(B) = \frac{sin(82)*24}{29}$

$sin(B) = 0.8195$

$B = sin^{-1}(0.8195)$

$B = 55.0$

m<B = 55°

Find m<A:

m<A = 180 - (82 + 55) => sum of angles in a triangle.

= 180 - 137

m<A = 43°

Find a using the law of sines:

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

$\frac{a}{sin(43)43} = \frac{24}{sin(55)}$

Cross multiply

$a*sin(55) = 25*sin(43)$

$a = \frac{25*sin(43)}{sin(53)}$

$a = 20$ (approximated)

8 0

3 years ago

I need help and a explanation please

Zanzabum

Answer:

$6.48

Step-by-step explanation:

It would be $6.48 because 1.60 times 4 1/2 is 7.2 and if you do 10% of 7.2 you get B.

3 0

3 years ago