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3 years ago

Help me and does anyone like kpop

Mathematics

2 answers:

4vir4ik [10]3 years ago

4 0

Answer:11/6 i think

Step-by-step explanation:i like kpop who doesn't

Serggg [28]3 years ago

3 0

The answer is 1 1/6.

2/3+1/4+1/4

=2/3+2/4

=2/3+1/2

=4/6+3/6

=7/6

=1 1/6

As for the second question, yes.

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FOR EASY BRAINLIEST!!! ANSWER WITH EXPLANATION: 1. 2. 3. 4.

spin [16.1K]

Answer:

1) 2

2) 5

3) 6

4) 0

6 0

2 years ago

Can someone help me please ???????

Inessa [10]

Answer:

d=1

Step-by-step explanation:

Factor d^2 - 2d - 8 into (d-4)(d+2)

Move -2/d+2 onto the other side, changing it into 2/d+2.

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4}+\frac{2}{d+2} = 0$

Let the empty side equal zero.

Add 3/d-4 and 2/d+2

$\frac{5d-2}{(d+2)(d-4)}$

Then add that to -3d.

$\frac{2d-2}{(d+2)(d+4)}$

Multiply 0 by d+2 and d-4 to get 2d-2 by itself.

2d=2

d=1

I can't edit the equation, but it's d-4 althroughout the question. Sorry for being so slow.

6 0

2 years ago

Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min

kow [346]

Answer:

$h=40t+9700$

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, $t_1=15$ min, the elevation, $h_1= 10,300$ feet and

at the time $t_2= 30$ min, the elevation, $h_2=10,900$ feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let $h$ be the elevation at any time instant $t$ , so the linear relation among these quantities is

$h=mt+C_0\;\cdots(i)$

where $m$ is the rate of change of elevation with respect to time and $C_0$ is constant.

The change in the elevation, $\Delta h=h_2-h_1= 10,900-10,300=600$ feet.

and the change in time, $\Delta t=t_2-1_1=30-15=15$ min.

So, change in the elevation in unit time,

$m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40$ feet/min.

Now, from equation (i)

$h=40t+C_0$

As the elevation, $h=h_1$ at time $t=t_1$ , so

$10,300=40\times15+C_0$

$\Rightarrow C_0=9700$

Hence, the required equation is

$h=40t+9700$

where the elevation, $h$ , is in feet and time, $t$ , is in minutes.

3 0

2 years ago

Factor the GCF: −6x4y5 − 15x3y2 + 9x2y3 (5 points)

MissTica

-6x^4y^5-15x^3y^2+9x^2y^3

The GCF OF -6, -15, & 9, is -3
The GCF OF x's is x^2
The GCF OF y's is y^2
These are the number of x's and y's that each term has.
-3x^2y^2(2x^2y^3+5x-3y)
LETTER B

3 0

3 years ago

Read 2 more answers

The number of cases of a new disease can be modeled by the quadratic regression equation y = -2x^2 + 40x + 8. What is the best p

Stels [109]

Answer:

158 cases

Step-by-step explanation:

Given tbe quadratic regression model :

y = -2x^2 + 40x + 8

y = number of cases of a new disease

x = number of years

The predicted number of cases of a new disease in 15 years can be calculated thus ;

Put x = 15 in the equation ;

y = -2(15)^2 + 40(15) + 8

y = - 2 * 225 + 600 + 8

y = - 450 + 600 + 8

y = 158

158 cases

5 0

2 years ago