So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=

so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
Answer:
n = 10
Step-by-step explanation:
given m varies directly as n then the equation relating them is
m = kn ← k is the constant of variation
to find k use the condition m = 6 when n = 5
6 = 5k ( divide both sides by 5 )
k =
= 1.2
m = 1.2n ← equation of variation
when m = 12 , then
12 = 1.2n ( divide both sides by 1.2 )
10 = n
Answer:
Option c) y=
is correct
The value of y is 3
Step-by-step explanation:
Given equation is
To solve the given equation for y
(converting mixed fraction to normal fraction )
(taking LCM 25 )
(adding the terms )
(now convert fraction into mixed fraction )
Therefore y=
Option c) y=
is correct
The value of y is 3