We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Ahh that’s very very very very swag
Answer:
x²-6x+y²-4y=-4
Step-by-step explanation:
We know the circle equation stands like this:
(x-a)² + (y-b)² = R²
and (a,b) is center
and R stands for Radius
so in this case:
center = (3,2)
R = 3
So
(x-3)² + (y-2)² = 9
x²-6x+9 + y²-4y+4=9
x²-6x+y²-4y=-4
X * 3 = 270
Solving for x, x = 90
So one side is 90m and the other is 3m.
Now find entire perimeter 90+90+3+3=180+6=186m
