All categories

3 years ago

1. Could the number 0000 appear in a table of random digits? How likely is this?

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

Yes cause it just can

Alex3 years ago

4 0

Yes,

probability = favorable outcomes/ total outcomes

to calculate the probability for this to occur, we use nCr ( nCr = n!/r!)

there are total 10 digits

so probability of the number 0000 appear in a table of random digits=

(1*1*1*1)/(10C1 * 10C1 * 10C1 * 10C1)

= 1/10000

You might be interested in

At a hockey game, a vendor sold a combined total of 148 sodas and hot dogs. The number of sodas sold was three times the number

AleksandrR [38]

Answer:

37 hot dogs and 111 sodas

Step-by-step explanation:

148 divided by 4= 37

148 - 37= 111

if the number of sodas was three times it would have to be broken up into three groups making the hot dogs 37 and sodas three times the amout would be 111. hope this helped sorry for any spelling mistakes

3 0

3 years ago

Read 2 more answers

What is the simple subject of I could feel the rain on my left shoulder.

ahrayia [7]

This a dang easy question. Ask yourself,what is the sentence about?

7 0

3 years ago

Can someone help me please??? <br> what is BC?

astraxan [27]

Answer:

3.5

Step-by-step explanation:

3 0

3 years ago

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

3 years ago

You are betting on a game with an expected value of -$0.33. What does this mean?

Maurinko [17]

I like to think of the - or under as the less likely to happen like a cat beating up a bear u don’t want to put your money on the cat so everyone puts there money on the bear making the bear the over and the cat the under

6 0

2 years ago