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3 years ago

Solve for n: -6(n-8)=4(12-5n)+14n

Mathematics

2 answers:

photoshop1234 [79]3 years ago

6 0

Answer: use calculated

Step-by-step explanation:

Calculator

kondaur [170]3 years ago

4 0

Answer:

Everything

Step-by-step explanation:

-6(n-8)=4(12-5n)+14n Given

-6n+48=48-20n+14n Distribute

-6n+48=48-6n Simplify

-6n=-6n Subtraction Property of Equality(Subtract 48 from both sides)

n=n Division Property of Equality(Divide both sides by -6)

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-Dominant- [34]

B. 1.67
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3 years ago

Add 2 1/4 hours to 6 hours 20 minutes please show the work

Scrat [10]

Answer:

Step-by-step explanation:

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4 years ago

Read 2 more answers

Joe drops a pebble into the sea. The pebble drops 2 inches every second. How many inches below sea level does it drop after 6 se

stellarik [79]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Consider xưy" – 14xy' + 56y = 0. Find all values of r such that y=x" satisfies the differential equation for x > 0. Enter as

beks73 [17]

I bet the ODE is supposed to read

$x^2y''-14xy'+56y=0$

Then if $y=x^r$ , we have $y'=rx^{r-1}$ and $y''=r(r-1)x^{r-2}$ , and substituting these into the ODE gives

$r(r-1)x^r-14rx^r+56x^r=0\implies r(r-1)-14r+56=r^2-15r+56=0$

Solving for <em>r</em>, we find

$r^2-15r+56=(r-8)(r-7)=0\implies \boxed{r=8\text{ or }r=7}$

so that $y_1=x^8$ and $y_2=x^7$ are two fundamental solutions to the ODE. Thus the general solution is

$\boxed{y(x)=C_1x^8+C_2x^7}$

Given that $y(1)=4$ and $y'(1)=3$ , we get

$\begin{cases}4=C_1+C_2\\3=8C_1+7C_2\end{cases}\implies C_1=-25\text{ and }C_2=29$

So the particular solution is

$\boxed{y(x)=29x^7-25x^8}$

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4 years ago

What are the zeros of the graphed function?

Zanzabum

Answer:

Option C

Step-by-step explanation:

Zeros of a function are also called as x-intercepts of a function, which means where the graph/function intersects the x-axis.

In the image we see the graph intersects the x-axis at three points

x=0 , x=2 , x=4 so our answer is option C

6 0

3 years ago