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krek1111 [17]
3 years ago
13

Determine whether each relationship below is true or false.

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

1. True

2. False

3. True

4. False

5. True

Step-by-step explanation:

For 1, you want to see the reduced fraction of 2/6 so you want to divide 2/6 by 2, it is 1/3 and 2/3 is greater than 1/3.

For 2, you want to multiply 5 by 2. and then do the same thing for 6, 6 x 2. Now you want to see if they match.

For 3, you want to make both fractions into decimals so 1/8 is 0.125 and 1/4 is 0.25 and see which is larger.

For 4, you want to see if you can simplify any of them. 2/4 can be simplifed to 1/2. So, it is false because you can see that 2/4 is the same as 1/2

For 5, you want to divide both fractions by 2, so 4/10 would be 2/5 and 4/6 would be 2/3. So it is true.

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Melody stated that the sum of a positive and a negative integer equals a negative integer or 0.
erik [133]
(a) I'd say sometimes true. 3 + -7= -4 , -5 + 3= -2 , 8+-5=3, 7+-7=0

(b)  I'm not too sure about this one but I what i know is that if the positive number is higher than the negative number it will be a positive. If you are adding both a negative number and a positive number that is the same value it will be 0. And if you are adding a negative that is higher than the positive it will be a negative number. 

I hope this helped a bit.. (: 
4 0
3 years ago
what is the solution to this system of linear equations? 2x y = 1 3x – y = –6 (–1, 3) (1, –1) (2, 3) (5, 0)
Nitella [24]
Hello,

2x+y=1
3x-y=-6

==>5x=-5
==>x=-1 and y=1-2*(-1)=3
Sol={(-1,3)}

Answer A

8 0
3 years ago
Read 2 more answers
In a box there are two prizes that are worth $4, a single prize worth $20, and a single prize worth $200. A player will reach in
Ronch [10]

Answer:

57

Step-by-step explanation:

The player has a 1/4 chance of drawing any of the 4 prizes. This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $20 is 1/4 and the probability of drawing a prize of $200 is also 1/4. To find the fair price of the game, we have to calculate the expected value that the player will gain. This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all the obtained values togueter. Thus, the fair price of the game is

4 * \frac{1}{2} + 20 * \frac{1}{4} + 200 * \frac{1}{4} = 57

6 0
3 years ago
Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10
Mashutka [201]

\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

2 \: ( \: x + 1 \: ) - 3

Plugging in the value "x\:=\:6" in the above expression, we have

= 2 \: ( \: 6 + 1 \: ) - 3

= 2 \: ( \: 7 \: ) - 3

= 14 - 3

= 11

<h3><u>Note</u>:-</h3>

\sf\red{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

5 0
3 years ago
If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t
vivado [14]
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.

Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line

y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)

y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)

6 0
3 years ago
Read 2 more answers
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