36 x p = 5p x 7.5 solve for p
1 answer:
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Question 1:
Multiply both sides of the proportion by 35.
You get.
7(x-1) = 4x+2
7x-7 = 4x+2
Now, add both sides by 7 and subtract both sides by 4x
3x = 9
Divide both sides by 3
x=3
Question 2:
Multiply both the numerator and the denominator of
by 3.
We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.
Set the numerator equal to the numerator and the denominator equal to the denominator.
3x+3 = 15
3x+9 = 21
If you solve both of these, you get x=4 for both.
That's your answer.
Hope this helps! :)
Multiply both sides of the proportion by 35.
You get.
7(x-1) = 4x+2
7x-7 = 4x+2
Now, add both sides by 7 and subtract both sides by 4x
3x = 9
Divide both sides by 3
x=3
Question 2:
Multiply both the numerator and the denominator of
We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.
Set the numerator equal to the numerator and the denominator equal to the denominator.
3x+3 = 15
3x+9 = 21
If you solve both of these, you get x=4 for both.
That's your answer.
Hope this helps! :)
Answer:
52% are girls
Step-by-step explanation:
We know that there are 650 sixth-graders and 338 of them are girls, we are then asked to find the percentage of how many are girls.
We have the fraction 338 over 650 but need to reduce it.
To solve this, we need to find the GCF of 650 and 338, which is 26, so divide both the numerator and denominator by 26.
Now divide the 13 and 25 :
13 / 25 = 0.52
0.52 * 100 = 52%
Therefore, 52% of the sixth-graders in the school are girls