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AVprozaik [17]
3 years ago
15

3x–8=0.5(8x+4) Solve for X

Mathematics
2 answers:
frez [133]3 years ago
8 0
Your answer is x equals -10
BabaBlast [244]3 years ago
3 0
3x-8=4x-2 x will bd -10
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Multiply 5,5,5,5 4 times which gives me 625
k0ka [10]

Answer:

Confusion

Step-by-step explanation:

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3 years ago
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2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?​
topjm [15]

Answer:

1.25

Step-by-step explanation:

Find the average.

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2.5/2

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6 0
3 years ago
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
A rectangular pyramid has a volume of 160 cubic feet. Find two possible sets of measurements for the base area and height of the
muminat

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ \cline{1-1} V=160 \end{cases}\implies 160=\cfrac{Bh}{3}\implies 480=Bh \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} 480=&2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 5\\ &8\cdot 60\\ &32\cdot 15 \end{cases}~\hspace{5em}\stackrel{B}{8}\times\stackrel{h}{60}\qquad \qquad \stackrel{B}{32}\times\stackrel{h}{15}

4 0
3 years ago
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