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Dmitry_Shevchenko [17]
3 years ago
6

How do I solve for tan(p)

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0
Tan = opp/adj. so from P, tangent would equal 12/16, when reduced equals 0.75. I hope this helps out!
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3. What is the radius of a circle whose area is 64π cm squared?
nataly862011 [7]

Answer:

Area = 64π

Area \: = \pi {r}^{2}Area=πr

2

64 \: \pi \: = \pi {r}^{2}64π=πr

2

{r}^{2} = \dfrac{64\pi}{\pi}r

2

=

π

64π

{r}^{2} = 64r

2

=64

r \: = \: \sqrt{64} = 8r=

64

=8

Radius = 8 units

Finding the Diameter -

Diameter = Radius x 2 = 8 x 2 = 16 .

\bold{Diameter \: is \: 16 \: units}Diameteris16units

8 0
3 years ago
Jake wants to buy a skateboard. The one he is looking at cost $295. It is on sale for 35% off. How much will Jake save if he buy
Aleks [24]

Answer:

191.5

Step-by-step 103.5 explanation:

295 x 0.35(which is 35%) = 103.5

295 - 103.5 = 191.5

hope this helps

3 0
3 years ago
Read 2 more answers
Find the value of y in the solution to the system of equations shown. 3y=18x+6 y=2x+14
ololo11 [35]

Answer:

y=14

Step-by-step explanation:

because I solved it and got 14 ......

5 0
2 years ago
Evaluate exactly the value of the integral from -1 to 0 (2x^4+8x)^3 (4x^3+4),dx. Include the use of substitution and the antider
ddd [48]
Hello,

Let's be

 z=2x^4+8x \\
dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\

 \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\
= 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}=
\left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648

3 0
3 years ago
2x - y = 5
goldfiish [28.3K]
Im pretty sure that the answer it is A. 7
because if you subtract 2 from 7 you get 5
6 0
3 years ago
Read 2 more answers
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