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3 years ago

Determine the direction that this parabola opens y=4x^2+8x+2

1 answer:

8 0

For this case we have a quadratic equation of the form:
$ax ^ 2 + bx + c
$
What we must keep in mind to know which direction opens the parabola, is the value of a.
We have two options:
If a <0 the parabola opens down
If a> 0 the parabola opens up
We have the following equation:
$y = 4x ^ 2 + 8x + 2
$
We observed that:
$a = 4 (a\ \textgreater \ 0)
$
Therefore, the parable opens up.
Answer:
the direction that this parabola opens is:
Upwards

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$\qquad\qquad\huge\underline{{\sf Answer}}$

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2 years ago

Which of the following best describes the intersection of two planes? (Points : 5)

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3 years ago

2 x - 5 + 7 y - 3 = 9 x - 1 - y -8 Solve For X AND Y (SHOW WORK PLEASE)

Maru [420]

Answer:

$\large\boxed{\sf x = \frac{8y+1}{7} }$

$\large\boxed{\sf x = \frac{7x-1}{8} }$

Group the Variable's:

2 x - 5 + 7 y - 3 = 9 x - 1 - y -8

2x -9x + 7y +y = -1 -8 +5 + 3

-7x + 8y = -1

From this find x and y

For X

-7x + 8y = -1

-7x = -1 -8y

7x = 8y + 1

x = (8y +1)/7

For Y

-7x + 8y = -1

8y = -1 +7x

y = (7x -1)/8

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2 years ago

Read 2 more answers