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myrzilka [38]
3 years ago
10

A polynomial is shown below.

Mathematics
2 answers:
fredd [130]3 years ago
5 0

Answer:

A, -9

Step-by-step explanation:

Alja [10]3 years ago
3 0

Answer:

The remainder is -9

So, Option A is correct.

Step-by-step explanation:

We need to divide the polynomial 4x^3-7x^2-13 by x-2 and determine the remainder.

The division is shown in the figure attached.

The remainder is -9

So, Option A is correct.

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1,383,098 in word form
vlabodo [156]
One million three hundred eighty-three thousand ninety-eight<span />
7 0
3 years ago
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The function p(x) = _2(x _ 9)2 + 100 is used to determine the profit on T-shirts sold for x dollars. What would the profit from
Valentin [98]

Answer:

Option (b) is correct.

The profit  from sales if the price of the T-shirts were $15 a pieces is $28.

Step-by-step explanation:

Given : The function p(x)=-2(x-9)^2+100 is used to determine the profit on T-shirts sold for x dollars.

We have to find the profit from sales if the price of the T-shirts were $15 a pieces.

Consider the given profit function  p(x)=-2(x-9)^2+100

For the profit, if the price of a t-shirt is $ 15

Put x = 15, we have,

p(15)=-2(15-9)^2+100

Simplify, we have,

p(15)=-2(6)^2+100=-2\cdot 36+100

Also,  p(15)=-72+100=28

Thus, we get,  The profit  from sales if the price of the T-shirts were $15 a pieces is $28.

5 0
3 years ago
Read 2 more answers
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
Everything just the first one, please. Asap, thanks in advance!
alekssr [168]
Question number one is 2/3
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4 years ago
Help PLEASE<br> I need help rn plsssssss I beg youu
olasank [31]
Rectangular prism Area=2(wl+hl+hw) in this case, the length (l) is 9m, the width (w) is 8m, the height (h) is 9m. Just plug everything into the formula: 2(8*9+9*9+9*8)=450m^3. Hopefully It helped. Have a good day.
3 0
3 years ago
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