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3 years ago

PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

Mathematics

1 answer:

Lesechka [4]3 years ago

8 0

Answer:

So the 1st, 2nd, & 3rd graphs all show continuous data. (I'll attach an image to show which ones I'm talking about)

Explanation:

This is because with continuous data, all points need to connect and it needs to continue. The 4th graph (with just points) would be discrete.

I hope this helps!! :)

Sorry I took so long...

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Miles and kilometers are twi different scales for measuring distances. A 5-kilometer race is approximately 3.1 miles, and a 10-k

sveta [45]

Answer:

$x=\dfrac{y}{0.62}$

Step-by-step explanation:

$5\ \text{km}=3.1\ \text{miles}\\\Rightarrow 1\ \text{km}=\dfrac{3.1}{5}=0.62\ \text{miles}$

$10\ \text{km}=6.2\ \text{miles}\\\Rightarrow 1\ \text{km}=\dfrac{6.2}{10}=0.62\ \text{miles}$

Let $y$ be the distance in miles. So distance in km is given by

$x=\dfrac{y}{0.62}$ .

The equation that shows the approximate distance in kilometers as a function if the distance in miles is $x=\dfrac{y}{0.62}$ .

7 0

3 years ago

What is the measure of the missing angle?)<br><br>Please explain how u got the answer so I can learn

anygoal [31]

Step-by-step explanation:

let x be the another angle

x+40=90

x=90-40

x=50

The measure of missing angle is 50

hope it helps

7 0

3 years ago

Read 2 more answers

A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if

topjm [15]

Answer:

a) The expected value is $\frac{-1}{15}$

b) The variance is $\frac{49}{45}$

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is $\binom{10}{2}$ .

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is $\binom{5}{2}$ . Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is $\binom{5}{1}\cdot \binom{5}{1}$ . So, we define the following probabilities.