Using the median concept, it is found that the interquartile range of Sara's daily miles is of 21 miles.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference of the quartiles.
The ordered data-set is given as follows:
65, 72, 86, 88, 91, 93, 97
There are 7 elements, hence the median is the 4th element, of 88. Then:
- The first half is 65, 72, 86.
- The second half is 91, 93, 97.
Since the quartiles are the medians of each half, the have that:
- The first quartile is of 72 miles.
- The third quartile is of 93 miles.
- The interquartile range is of 93 - 72 = 21 miles.
More can be learned about the median of a data-set at brainly.com/question/3876456
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Answer:
180 CDs
Step-by-step explanation:
So if Sam has 84 CDs, and the ratio from Sam to Alice is 7:8, we can do 84/7=12 so each number is equal to 12. Then we add up 7 and 8 and get 15, so we do 15*12 and we get 180.
Answer:
The probability that a household has at least one of these appliances is 0.95
Step-by-step explanation:
Percentage of households having radios P(R) = 75% = 0.75
Percentage of households having electric irons P(I) = 65% = 0.65
Percentage of households having electric toasters P(T) = 55% = 0.55
Percentage of household having iron and radio P(I∩R) = 50% = 0.5
Percentage of household having radios and toasters P(R∩T) = 40% = 0.40
Percentage of household having iron and toasters P(I∩T) = 30% = 0.30
Percentage of household having all three P(I∩R∩T) = 20% = 0.20
Probability of households having at least one of the appliance can be calculated using the rule:
P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)
P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20 P(at least one of the three) = 0.95
The probability that a household has at least one of these appliances is 0.95
Answer:
Step-by-step explanation:
Correct option is
D
[1,(1+π)
2
]
f(x)=(1+sec
−1
(x))(1+cos
−1
(x))
Here the limiting component is cos
−1
(x), since the domain of cos
−1
(x) is [−1,1].
Therefore,
f(1)=(1+0)(1+0)
=1
f(−1)=(1+π)(1+π)
=(1+π)
2
Hence range of f(x)=[1,(1+π)
2
]
It has a minimum value at x = 3 and f(x) = 4
Vertex form is
f(x) = a(x - 3)^2 + 4 where a is some constant to be found
From the graph when x = 5 f(x) = 15, so
15 = a * 2^2 + 4
a = 15-4/4 = 11/4
so our equation is f(x) = 11/4(x - 3)^2 + 4
