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xenn [34]
4 years ago
8

A certain comet has a parallax 1/40 as large as the moon. How far away is it (compared to the Moons distance)? Show Work

Physics
1 answer:
Ad libitum [116K]4 years ago
3 0
The distance and parallax are inversely related. We can find the distance using the following equation:

d= \frac{1}{p}

where d is distance and p is parallax.

We are given the parallax of the comet relative to the moon, and we are looking for the distance to the comet relative to the moon's distance, so wee can plug in the following value:

d= \frac{1}{ \frac{1}{40} }

The distance is 40 times as far away as the moon.
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If you are in a spaceship that is sitting on the surface of a planet, you feel your weight. How does this compare to the weight
nordsb [41]

Answer:

You will feel more weight if it is accelerating out of the planet.

You will feel less weight if it is accelerating towards the planet.

Explanation:

The weight that you are observing or feeling is basically due to the change in acceleration of your fall or rising up in the spaceship. When the acceleration is stationary on the surface, you experience your normal weight due to the gravitational acceleration of that planet.

When the spaceship accelerates above or out of the planet you experience acceleration more than the acceleration of gravity hence more weight.

When the spaceship accelerates towards the planet you experience acceleration less than the acceleration of gravity hence less weight.

If the spaceship is free falling at the gravitational acceleration you experience a zero weight

8 0
4 years ago
A train moving at 5 m/sec passed a track gang and then accelerated uniformly a rate of 1.2 m/sec/sec for 5 min. How far did the
Amanda [17]

Answer:

S = V0 t + 1/2 a t^2

S = 5 m/s * 300 s + 1/2 * 1.2 m/s * (300 s^2)

S = 1500 m + .6 * 90000 m = 55,500 m

Check:     V0 = 5 m/s

                V2 = V0 + a t  = 5 + 1.2 * 300 = 365 m/s

Vav = (V1 + V2) / 2 = (5 + 365) / 2 = 185 m/s     (note uniform motion)

S = 185 * 300 = 55,500 m

We calculated V2 above at 365 m/s  the speed after 300 sec

3 0
3 years ago
Which item could you use in place of an ammeter to demonstrate that a
love history [14]

Answer:

the answer is D

Explanation:

6 0
3 years ago
Which of the following describes velocity only in terms of metric units?
Lelechka [254]

Choice 'D' describes speed in the metric units 'meter' and 'second'.
With no mention of direction, it can't be called 'velocity'.

8 0
4 years ago
1. If some unimaginable calamity destroyed the Sun, using the astronomical unit for the Earth-Sun distance and the value for the
Vsevolod [243]

Answer:

8 minutes and 20 seconds

Explanation:

Average Distance between Earth and Sun: 150 million km   = 1.5 * 10^{8} km

Velocity of light: 3 * 10^{8} \ m/s   =   3 * 10^{5} \ km/s

Time = Distance/Speed

or Time = 1.5 * 10^{8} \ km / 3 * 10^{5} \ km/s

= 5 * 100

= 500 seconds

⇒ Time = 8 minutes and 20 seconds

8 0
3 years ago
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