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mojhsa [17]
3 years ago
9

To win the game, a place kicker must kick a football from 30m from the goal, and the ball must clear the crossbar which is 3.05

m high. When kicked, the ball leaves the ground with the speed of 19 m/s at the angle of 37.2° from the horizontal. Acceleration of gravity is 9.8 m/s^2
How much vertical distance does the ball clear the crossbar?
Physics
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

Explanation:

Ignore air resistance

The horizontal velocity is

vx =19cos37.2 = 15.134 m/s

The ball travels 30 m in a time of

30 / 15.134 = 1.982 s

In that time, the ball will be at an altitude of

s = vy₀t + ½at²

s = 19sin37.2(1.982) + ½(-9.8)1.982² = 3.5137... m

so the ball clears the bar by

h = 3.5137 - 3.05 = 0.4637... = 0.46 m

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g100num [7]

Answer:50.39 m/s,

40.46 m

Explanation:

Given

launch angle=34^{\circ}

Range=240 m

We know that Range =\frac{u^2sin2\theta }{g}

240=\frac{u^2sin(68)}{9.81}

u=50.39 m/s

(b)maximum height of projectile is given by

H=\frac{u^2sin^2\theta }{2g}

H=\frac{50.39^2(sin34)^2}{2\times 9.81}

H=40.46 m

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Because noble gases has full of 8 electron in her external cell......
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An asteroid is on a collision course with Earth. An astronaut lands on the rock to bury explosive charges that will blow the ast
forsale [732]

Answer:

The maximum radius the asteroid can have for her to be able to leave it entirely simply by jumping straight up is approximately 1782.45 meters

Explanation:

Whereby the height the astronaut can jump on Earth = 0.500 m, we have the following kinematic equation;

v² = u² - 2·g·h

Where;

v = The final velocity

u = The initial velocity

g = The acceleration due to gravity ≈ 9.8 m/s²

h = The height she jumps

At the maximum height, h_{max} = 0.500 m, she jumps, v = 0, therefore, we have;

0² = u² - 2·g·h_{max}

u² = 2 × 9.8 × 0.5 = 9.8

u = √9.8 ≈ 3.13

u = 3.13 m/s

Her initial jumping velocity ≈ 3.13 m/s

Escape velocity, v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{r} }

Where;

M = The mass of the asteroid

G = The Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)

r = The radius of the asteroid

The average density of the Earth = 5515 kg/m³

The mass of the asteroid, M = Density × Volume = 5515 kg/m³× 4/3 × π × r³

The escape velocity, she has, v_e ≈ 3.13 m/s is therefore;

3.13 = \sqrt{\dfrac{2 \times 6.67408 \times 10^{-11} \times 5515 \times \frac{4}{3} \times \pi \times r^3}{r} } = r \times \sqrt{3.084 \times 10^{-6}}

r = \dfrac{3.13}{ \sqrt{3.084 \times 10^{-6}}} \approx 1782.45

Therefore, the maximum radius of the asteroid can have for her jumping velocity to be equal to the escape velocity for her to be able to leave it entirely simply by jumping straight up = r ≈ 1782.45 meters.

7 0
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A rock is dropped into the Grand Canyon. It takes 18 seconds to hit the bottom. Calculate how deep the canyon is.
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The distance it falls is given by
x = (1/2)at^2
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x = (1/2)(9.8)(18)^2
x = 1587.6 m
The answer is 1587.6 meters

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Answer:

Solar system is a part of Milkyway Galaxy.

Explanation:

Mikyway is a Galaxy or we can compare it with a family of many members (collectively) ane Solar system is a part of mikyway galaxy or we can compare it with a member of the family!

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