Answer:
Net force on the car will be
Explanation:
We have given mass of the car m = 850 kg
Initial velocity of the car u = 45 km/hr
As the car finally stops so final velocity of car v = 0 m/sec
Distance travel for stooping of car s = 1.8 cm = 0.018 m
From third equation of motion
So
So magnitude if acceleration will be
So net force on the car
So net force on the car will be
Answer:
27.22 F.
Explanation:
T ( t ) = T₀ + ( T₁ - T₀)
T ( t ) = 41 , T₀ = 0 , T₁ = 140 , t = 15
Put these values in the equation above
41 = ( 140 - 0 ) e^{-15k}
41/140 = e ^{-15k}
(41/140)^{1/3} = e ^{-5k}
Let after 20 minutes temperature becomes T
T = 0 + 140 e^{-k20}
T / 41 = e^{-5k }
= (41/140)^{1/3}
T = 41 X (41/140)^{1/3}
= 27.22 F.
Answer:
the height reached is = 0.458 [m]
Explanation:
We need to make a sketch of the ball and see the location of the reference point where the potential energy is zero. But the kinetic energy will be defined by the following expression:
Replacing the values on the equation we have:
This kinetic energy will be transformed in potential energy in the moment when the ball starts to rolling up. Therefore the maximum height reached by the ball depends of the initial velocity given to the ball.
Now we have:
In that moment when the ball reach the 0.45 [m] the potencial energy will be maximum and equal to the kinetic energy when the ball has a velocity of 3[m/s]
