Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
Now, distance covered by car is :
Hence, this is the required solution.
The relationship between acceleration, velocity and radius
is given as:
a = v^2 / r
Since we are given a diameter of 45 m, hence the radius is
22.5 m.
a = (16 m/s)^2 / 22.5 m
a = 11.38 m/s^2
In 2 significant figures:
<span>a = 11 m/s^2</span>
Answer:
Decrease the voltage,and do not change the resistance,the current will also decrease
Explanation:
Decrease the voltage,and do not change the resistance, the current will also decrease, because voltage is directly proportional to current
ANSWER: (ROLE of Producers in the cycle:totake in carbon dioxide from the atmosphere during photosynthesis and release carbon dioxide during respiration,ROLE of Consumers:to contribute to the carbon cycle when they perform respiration and expel carbon dioxide into the atmosphere)
Hope this Helps SOMEONE!!
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Answer: The gauge pressure of the air in the tires is 179.5 kPa.
Solution :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = Atmospheric pressure + gauge pressure = 101 kPa + 165 kPa = 266 kPa
= final pressure of gas = ?
= initial volume of gas =
= final volume of gas =
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get the final pressure of gas.
Gauge pressure = Absolute pressure - atmospheric pressure = (280.5 - 101) kPa= 179.5 kPa
Therefore, the gauge pressure of the air in the tires is 179.5 kPa.