Answer:
(x-2)(x-3)
Step-by-step explanation:
1 42.5* and 3 95*, the sum of all the angles =360*, so Angle J = L and M=K, Angle 1 =M/2
Answer:
Best predicted value of y' = 86.16 kg
Step-by-step explanation:
Given,
n = 100
Range of heights = 138 - 190cm
Range of weight = 39 to 150 kg
x' =167.46 cm
y' = 81.44 kg
r = 0.108
p value = 0.285
y = - 105 + 1.08x
Significance level = 0.05
We reject H0 since pvalue, 0.285 is less than significance level of 0.05.
Therefore,
Given height of adult male, x = 177 cm
y = - 105 + 1.08x
The best predicted value of y' =
y' = - 105 + 1.08(177)
y' = 86.16 kg
The best predicted value of y' is 86.16kg
Answer: (141.1, 156.48)
Step-by-step explanation:
Given sample statistics : 
a) We know that the best point estimate of the population mean is the sample mean.
Therefore, the best point estimate of the mean weight of all women = 
b) The confidence interval for the population mean is given by :-
, where E is the margin of error.
Formula for Margin of error :-
Given : Significance level : 
Critical value : 
Margin of error : 
Now, the 90% confidence interval for the population mean will be :-
Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)
Answer:
The cafeteria provides three meals per day.
<u>Reason 1</u>
Yes, they vary directly
As number of days increases ,Total number of meals i.e
1st day ⇒ 3
2nd day⇒6
3 rd day⇒9
4th day⇒12
......................
.........................
increases.
Total number of Meals = k×Number of days
But there is another possibility also
<u>Reason 2</u>
1 st day ⇒ 3
2nd day ⇒3
3rd day⇒ 3
.....................
.....................
As you can see from the above expression On each day number of meals is
constant.
So we can say that ,
On each Day=Constant amount of meal=3
So, there is no Proportionality between Days and Meal.
