To group an expression, means that the factors of the expression are to be separated in (), [] or {}.
An expression with a value of 80 is: ![2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=2%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
The number is given as:

Factorize

Factorize 40

Express
as an exponent

Express 20 as 4 x 5

Express 5 as 3 + 2
![80 = 2^2 \times ( 4 \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%204%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Express 4 as 2 + 2
![80 = 2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Hence, the above expression has a numerical value of 80
Read more about numerical expressions at:
brainly.com/question/24787226
Perpendicular lines, slope is opposite and reciprocal. so if the slope of line c is -4 then the slope of line d will be 1/4
Hope it helps
The answer to your question is $720
The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)
We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.
a^2 - b^2 = (a - b)(a + b)
In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.
a^2 = 25m^100 -----> take the square root of both sides
a = 5m^50
Then we can do the same for the b term.
b^2 = 121n^16 ----->take the square root of both sides
b = 11n^8
Now we can use both in the equation already given
(a - b)(a + b)
(5m^50 - 11n^16)(5m^50 + 11n^16)