Every Thursday, Matt and Dave's Video Venture has “roll-the-dice" day. A customer may choose to roll two fair dice and rent a se
cond movie for an
amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. For example, if the customer rolls a two and a four, a
second movie may be rented for $0.42. If a two and two are rolled, a second movie may be rented for $0.22. Let X represent the amount paid for a
second movie on roll-the-dice day. The expected value of X is $0.47 and the standard deviation of X is $0.15.
If a customer rolls the dice and rents a second movie every Thursday for 30 consecutive weeks, what is the approximate probability that the total
amount paid for these second movies will exceed $15.00?
I saw other questions for this but why is the standard deviation 0.15*sqrt of 30 and not 0.15*30 because I thought this is a linear transformation
1 answer:
You might be interested in
Answer:
48 green
Step-by-step explanation:
red : green
4 : 6
We want 32 red ribbons
Multiply each side by 8
red : green
4*8 : 6*8
32 : 48
Answer:
three and seventy-five hundredths or three point seven five
Step-by-step explanation:
<h3>
Answer:y and z</h3>
Step-by-step explanation:
<h2>bc y and z is in the alphabet </h2>
Answer:
bonjour voilà la réponse 4.55
Answer:
x=14
Step-by-step explanation: