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Andre45 [30]
2 years ago
14

Every Thursday, Matt and Dave's Video Venture has “roll-the-dice" day. A customer may choose to roll two fair dice and rent a se

cond movie for an
amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. For example, if the customer rolls a two and a four, a

second movie may be rented for $0.42. If a two and two are rolled, a second movie may be rented for $0.22. Let X represent the amount paid for a

second movie on roll-the-dice day. The expected value of X is $0.47 and the standard deviation of X is $0.15.

If a customer rolls the dice and rents a second movie every Thursday for 30 consecutive weeks, what is the approximate probability that the total

amount paid for these second movies will exceed $15.00?


I saw other questions for this but why is the standard deviation 0.15*sqrt of 30 and not 0.15*30 because I thought this is a linear transformation
Mathematics
1 answer:
german2 years ago
5 0

X = $13.38

Y = $2.00

v

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