Answer:
A = 76.85
B =65.28
Step-by-step explanation:
(30/100)A = 10 + (20/100)B
0.3A - 0.2B = 10 ...... equation (i)
(30/100)B + 35 = (20/100)A
0.2A - 0.3B = 35 ........ equation (ii)
From equation (i)
0.3A = 10 - 0.2B
A = (10 - 0.2b) / 0.3
A = 33.33 - 0.67B ........equation (iii)
Put equation (iii) into equation (ii)
0.2(33.33 - 0.67B) - 0.3B = 35
6.67 - 0.134B - 0.3B = 35
0.434B = 35 - 6.67
B = 28.33 / 0.434
B = 65. 275 = 65.28
Put B = 65.28 into equation (i)
0.3A - 0.2B = 10
0.3A - 0.2(65.28) = 10
0.3A - 13.056 = 10
0.3A = 10 + 13.056
A = 23.056/ 0.3
A = 76.85
Answer: If rounded it would be 13 (together not rounded).... If not its would be 12(not rounded)
Step-by-step explanation: 6.8 is about to 7,.... and 0.0 is just 0..... and 0.6 is close to 0.5 all together would be 13 but if we round it would be 12
Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.
Step-by-step explanation:
I suppose that the "legs" of a triangle rectangle are the cathati.
if L is the length of the shorter leg, 2*L is the length of the longest leg.
Now you can remember the relation:
Tan(a) = (opposite cathetus)/(adjacent cathetus)
Then there is one acute angle calculated as:
Tan(θ) = (shorter leg)/(longer leg)
Tan(φ) = (longer leg)/(shorter leg)
And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.
Then we need to find θ and φ.
Tan(θ) = L/(2*L)
Tan(θ) = 1/2
θ = Atan(1/2) = 26.57°
Tan(φ) = (2*L)/L
Tan(φ) = 2
φ = Atan(2) = 63.43°
Then the ratio between the larger acute angle and the smaller acute angle is:
R = (63.43°)/(26.57°) = 2.39
This means that the larger acute angle is 2.39 times the smaller acute angle.
Step-by-step explanation:
It is (A)95° by using External Angle Property of triangles.
BTW whats up with that order C-D-B-A
