Please help me on my homework! :) Its due tomorrow and I need help on numbers 3-6 thanks ;) (picture attached)
1 answer:
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Answer:
A.
Step-by-step explanation:
Hi there!
We are given right triangle PQR, with PR=5, RQ=12, and PQ=13
We want to find the value of sin(Q)
Let's first recall that sine is
In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse
So that means that sin(Q) would be
Substituting the values of PR and PQ gives sin(Q) as , which is A
Hope this helps!
Well... the segment FG = 4x + 3, the segment GH = 7x - 12, now, the
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.
thus, FG = GH
or
and fairly sure, you know how much that is.
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.
thus, FG = GH
or
and fairly sure, you know how much that is.