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Papessa [141]
3 years ago
12

A. A man weighs 185 lb. What is his mass in grams?

Mathematics
1 answer:
zalisa [80]3 years ago
8 0

Answer: About 83915 grams

.............................

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Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
Allisa [31]

Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0
3 years ago
An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.
____ [38]

A)

Earlier, The length of the angelfish  = 1 \frac{1}{2} inches

Now, the length of angelfish = 2 \frac{1}{3} inches

We have to determine the grown length of angelfish

=  2 \frac{1}{3} -  1 \frac{1}{2}

= \frac{7}{3}- \frac{3}{2}

LCM of '2' and '3' is '6',

= \frac{14-9}{6}

= \frac{5}{6} inch

Therefore, the angelfish has grown by \frac{5}{6} inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = \frac{1}{12} foot

So, \frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}

= 0.069 foot.

7 0
3 years ago
Read 2 more answers
Which is a real-world example of two planes intersecting?
leva [86]
The answer to the question above is the third choice, "a shelf on a wall". The shelf is usually made of rectangular pieces of materials that are then connected to each other to form quadrilaterals. The sides of the shelf are planes. 
8 0
3 years ago
Read 2 more answers
Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions
monitta
I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take z=y', so that z'=y'' and we're left with the ODE linear in z:

y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

Now suppose y has a power series expansion

y=\displaystyle\sum_{n\ge0}a_nx^n
\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}
\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}

Then the ODE can be written as

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0

\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0

All the coefficients of the series vanish, and setting x=0 in the power series forms for y and y' tell us that y(0)=a_0 and y'(0)=a_1, so we get the recurrence

\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x

We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}
4 0
3 years ago
What binomial is a factor of the trinomial x^2-5x+4
Svetradugi [14.3K]

Explanation:

Let the equation be

a

⋅

x

2

+

b

⋅

x

+

c

. To factorize multiplication of a and c i.e. ac so that sum of factors, if ac is positive (and difference if ac is negative) is equal to b. Now split b into these two components and factorization will be easy.

4 0
4 years ago
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