Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Answer:
0.3875
Step-by-step explanation:
Given that in a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this group selected hiking as their favorite outdoor activity whereas 35% of the women in the group selected hiking as their favorite outdoor activity
From the above information we find that
P(Men) = 0.75 and P(women) = 0.25 (since men:women = 3:1)
Out of men prob for not selecting hiking as their favorite outdoor activity

Out of women prob for not selecting hiking as their favorite outdoor activity

Prob for a randomly selected person that hiking is not his/her favorite outdoor activity = Prob (man and not selected activitiy) + P(women and not selected activity) (since men and women are mutually exclusive and exhaustive)
=
1/2
plsss mark brainliestt
Step-by-step explanation:
3/6
1.5/3
5/2.5
13-11 9/20 = 1 11/20 sooo G