Answer:
The mass of NaHCO3 required is 235.22 g
Explanation:
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Continuation of Question:
2NaHCO3(s) + H2SO4(aq) → Na2SO4(aq) + 2CO2(g) + 2H2O(l)
You estimate that your acid spill contains about 1.4 mol H2SO4. What mass of NaHCO3 do you need to neutralize the acid?
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The question requires us to calculate the mass of NaHCO3 to neutralize the acid.
From the balanced chemical equation;
1 mol of H2SO4 requires 2 mol of NaHCO3
1.4 would require x?
Upon solving for x we have;
x = 1.4 * 2 = 2.8 mol of NaHCO3
The relationship between mass and number of moles is given as;
Mass = Number of moles * Molar mass
Mass = 2.8 mol * 84.007 g/mol
Mass = 235.22 g
8 because atomic number is the same as number of protons, protons and electrons have the same amount so that the element is neither positive nor negative.
Answer:
96.92 K
Explanation:
Applying,
V/T = V'/T'..................... Equation 1
Where V = Initial Volume, T = Initial Temperature, V' = Final Volume, T' = Final Temperature.
Make T the subject of the equation
T = VT'/V'................. Equation 2
From the question,
Given: V = 268 mL, V' = 824 mL, T' = 25°C = (25+273) = 298 K
Substitute these values into equation 2
T = (268×298)/824
T = 96.92 K
Hence the Initial temperature of Nitrogen gas is 96.92 K
Answer: 2232 torr
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 750 torr
= final pressure of gas = ?
= initial volume of gas = 36.0 L
= final volume of gas = 15.0 L
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
The pressure will be 2232 torr if the volume changes to 15.0 L and the temperature changes to 78 °C, if the amount of gas stays the same.