When methane reacts with oxygen, the products are carbon dioxide (CO2) and water (H2O). How many grams of water are formed if 24 g of methane react completely with 96g of oxygen to form 66g of carbon dioxide? (include units)
1 answer:
Answer:
54 g
Explanation:
To solve this problem we will simply follow the Law of conservation of mass.
According to this law:
" The mass of product in the chemical reaction must be equal to the mass of reactant"
Given data:
mass of methane= 24 g
mass of oxygen= 96 g
mass of carbon dioxide= 66 g
mass of water= ?
Solution:
CH4 + 2O2 → CO2 +2H2O
24g + 96 g = 66 g + ?
120 g = 66 g + ?
120 g - 66 g = 54 g
so 54 g of waters are produce.
We can see that mass of water is equal to the sum of masses of reactant minus mass of product formed i.e mass of carbon dioxide.
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