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Vanyuwa [196]
4 years ago
6

When methane reacts with oxygen, the products are carbon dioxide (CO2) and water (H2O). How many grams of water are formed if 24

g of methane react completely with 96g of oxygen to form 66g of carbon dioxide? (include units)
Chemistry
1 answer:
VashaNatasha [74]4 years ago
4 0

Answer:

54 g

Explanation:

To solve this problem we will simply follow the Law of conservation of mass.

According to this law:

" The mass of product in the chemical reaction must be equal to the mass of reactant"

Given data:

mass of methane= 24 g

mass of oxygen= 96 g

mass of carbon dioxide= 66 g

mass of water= ?

Solution:

CH4 + 2O2 → CO2 +2H2O

24g + 96 g = 66 g + ?

120 g = 66 g + ?

120 g - 66 g = 54 g

so 54 g of waters are produce.

We can see that mass of water is equal to the sum of masses of reactant minus mass of product formed i.e mass of carbon dioxide.

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