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Mkey [24]
4 years ago
12

Can someone help me?

Chemistry
1 answer:
lbvjy [14]4 years ago
7 0

Yes that is what this site is for. You have a question and some one will answer

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Q.Can anyone explain the influence of soil solution pH on the nutrient availability of essential nutrients?​
igomit [66]

Answer:

pH Affects Nutrients, Minerals and GrowthBefore

a nutrient can be used by plants it must be dissolved in the soil solution. Most minerals and nutrients are more soluble or available in acid soils than in neutral or slightly alkaline soils.

Hope this helps

7 0
3 years ago
What type of protein penetrates to the interior of the plasma membrane but does not extend all the way through it?
ELEN [110]
The answer you are looking for is integral
7 0
4 years ago
Read 2 more answers
You have a solution with an unknown concentration of hcl, in order to determine the concentration of hcl you titrate 35.00ml of
slava [35]

Answer:-

0.648 M

Explanation:-

Volume of Ba(OH)2= 34.63ml/1000=0.03463 litre

Number of moles of Ba(OH)2 = 0.3275 M x 0.03463 litre

= 0.01134 moles

Since Ba(OH)2 has 2 OH in its formula,

Number of moles of OH- = 2 x 0.01134=0.02268 moles.

Volume of HCl= 35ml/1000 = 0.035 litre

At the end point number of moles of H+ = number of moles of OH-.

Number of moles of HCL= Concentration of HCl x Volume of HCl

∴ Concentration of HCl = 0.02268 moles/ 0.035 litre

= 0.648 moles/ litre

= 0.648 M

3 0
3 years ago
Why is vapor pressure higher in oil than water if water has stronger IMF’s?
Aleksandr-060686 [28]

Answer:

A liquid's vapor pressure is directly related to the intermolecular forces present between its molecules. The stronger these forces, the lower the rate of evaporation and the lower the vapor pressure.

Explanation:

4 0
3 years ago
Read 2 more answers
Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K
yawa3891 [41]

Answer:

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

Explanation:

Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)

Concentration of nickel ion = [Ni^{2+}]=x

Concentration of nickel complex= [[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L

Concentration of ethylenediamine = [en]=\frac{0.80 mol}{2 L}=0.40 mol/L

The formation constant of the complex = K_f=4.0\times 10^{18}

The expression of formation constant is given as:

K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}

4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}

x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}

x=3.125\times 10^{-19} mol/L

3.125\times 10^{-19} mol/L is the concentration of Ni^{2+}(aq) in the solution.

6 0
4 years ago
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