Answer:
0.322 × 10¹² /L
Step-by-step explanation:
Data provided in the question:
Number of cells counted with blue-stained granulofilamentous material
i.e number of RET = 100
The red blood cells count = 3.22 × 10¹² /L
Hematocrit = 30%
Now,
RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%
= [ 100 ÷ 1000 ] × 100%
= 0.1 × 100%
= 10%
also,
Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100
= [ 10 × 3.22 × 10¹² /L ] ÷ 100
= 0.322 × 10¹² /L
Answer:
10x+25
Step-by-step explanation:
