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mezya [45]
4 years ago
11

State Stoke's theorem​

Physics
1 answer:
Nataly_w [17]4 years ago
4 0

Answer:

Explanation:

Stokes' theorem relates a surface integral of a the curl of the vector field to a line integral of the vector field around the boundary of the surface.

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If the speed of a wave doubles while the frequency remains the same, it means
sattari [20]

Answer:

Explanation:

Velocity of a wave is describe as

velocity =Frequency × Wavelength

Mathematically

v = fλ

Hence, Frequency, F = v / λ

Wavelength λ = v/f

So, if the frequency is kept constant, wavelength of the wave becomes directly proportional to velocity of the wave.

And this implies that, as the speed double, the wavelength is double.

5 0
4 years ago
Gravitational energy can be negative?
AlladinOne [14]

answer:

yes

explanation:

At a separation of the surface of Earth (r=6400km) gravity wants pull the test mass closer and closer. ... So the work done by gravity is NEGATIVE. The gravitational potential energy is negative because us trying to do the opposite of what gravity wants needs positive energy.

6 0
3 years ago
Is oxygen a reactant or product
dezoksy [38]

Answer:

Methane and oxygen (oxygen is a diatomic — two-atom — element) are the reactants, while carbon dioxide and water are the products

Explanation:

3 0
3 years ago
Read 2 more answers
A car travels up a hill at a constant speed of 22 km/h and returns down the hill at a constant speed of 55 km/h. calculate the a
Ket [755]
The answer choice is 2.5
6 0
3 years ago
Compare the characteristics of 4d orbitals and 3d orbitals and compared the following sentences. Check all that apply
charle [14.2K]

Answer :

<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>

<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>

Explanation :

As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.

Hence, 4d orbitals would be larger in size than 3d orbitals.

Number of nodes is any orbital is n - 1 where, n is principal quantum number.

So, number of orbital in 4d is 3.

And number of orbital in 3d is 2.

So, options (b) and (e) are correct.

8 0
3 years ago
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