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Irina18 [472]
3 years ago
7

What is kinetic and potential energy?

Physics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

the energy produced in a body due to its motion is kinetic energy.

energy produced in a body due to its position is potential energy.

Afina-wow [57]3 years ago
7 0

Explanation:

kinetic energy is the energy possessed by a body in motion

Potential energy is the energy possessed by a body by virtue of its position with respect to a reference level

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The energy of a photon was found to be 3.38 x 10-19 J. Planck's constant is 6.63 x 10-34 J. S. Which color of light corresponds
GalinKa [24]

Answer:

The correct option is (c).

Explanation:

Given that,

The energy of a photon is, E=3.38\times 10^{-19}\ J

We need to tell the color of this light. We know that, the energy of a photon is given by :

E=\dfrac{hc}{\lambda}

Where

c is the speed of light

\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3.38 \times 10^{-19}}\\\\\lambda=5.88\times 10^{-7}\ m\\\\\lambda=588\ nm

The wavelength of yellow light is approx 580 nm. Hence, we can say that this photon corresponds to yellow light.

6 1
3 years ago
An inclinded plane makes work easier by increasing the distance and blank the force
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Hi! I believe your answer is decreasing. <u>An inclined plane makes work easier by decreasing the amount of effort force needed, but increases the distance</u>. I hope this helps you! Good luck and have a great day. ❤️✨

7 0
3 years ago
If I keep F constant in F=ma, what is the relationship between m and a?
Jobisdone [24]

Answer:

If F is a constant, we can take f = 1

f = m×a

ma = 1

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6 0
3 years ago
Which metal and nonmetal families are the most different and why
nevsk [136]

Answer:

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3 years ago
The critical angle for a special type of glass in air is 30.8 ◦ . the index of refraction for water is 1.33. what is the critica
Alina [70]
When light moves from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle above which there is no refracted light, and all the light is reflected. The value of this angle is given by
\theta_c = \arcsin ( \frac{n_2}{n_1} )
where n2 and n1 are the refractive indices of the second and first medium, respectively.

In the first part of the problem, light moves from glass to air (n_a=1.00) and the critical angle is \theta_c = 30.8^{\circ}. This means that we can find the refractive index of glass by re-arranging the previous formula:
n_g=n_1 =  \frac{n_2}{\sin \theta_c}= \frac{1.00}{\sin 30.8^{\circ}}=1.95

Now the glass is put into water, whose refractive index is n_w = 1.33. If light moves from glass to water, the new critical angle will be
\theta_c = \arcsin ( \frac{n_2}{n_1} )=\arcsin( \frac{n_w}{n_g} )=\arcsin( \frac{1.33}{1.95} )=\arcsin(0.68)=43.0^{\circ}
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