Step 
<u>Find the irreducible fraction in each ratio</u>
<u>case 1)</u> 
Divide by
boths numerator and denominator

<u>case 2)</u> 
Divide by
boths numerator and denominator

<u>case 3)</u> 
Divide by
boths numerator and denominator

<u>case 4)</u> 
Divide by
boths numerator and denominator

<u>case 5)</u> 
Divide by
boths numerator and denominator

<u>case 6)</u> 
Divide by
boths numerator and denominator

<u>case 7)</u> 
Divide by
boths numerator and denominator

<u>case 8)</u> 
Divide by
boths numerator and denominator

<u>case 9)</u> 
Divide by
boths numerator and denominator

<u>case 10)</u> 
Divide by
boths numerator and denominator

<u>case 11)</u> 
Divide by
boths numerator and denominator

<u>case 12)</u> 
Divide by
boths numerator and denominator

Step 
<u>Sort the ratios into bins</u>
1<u>) First Bin</u>
<u>
</u>



<u>2) Second Bin </u>
<u>
</u>


<u>3) Third Bin</u>



4<u>) Fourth Bin</u>
<u>
</u>




If you had a fair coin, the probability of seeing heads is 1/2, meaning you’d see heads 30 times
Answer: c: $65
Step-by-step explanation:
Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
Step-by-step explanation:
- Assume non-hypotenuse sides are 4 and 5, so tan =4/5=0.8 . Then hypotenuse is sqrt(16+25) = sqrt(41) So sides are 4,5,sqrt (41).