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2 years ago

Please help me out, i can not understand this, i will give a brainliest out to whoever can help me

Mathematics

1 answer:

marishachu [46]2 years ago

6 0

Answer:

So try 0-6

Step-by-step explanation:

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State the restrictions of 1-x-y/x+y

Ronch [10]

The restriction of the expression as given in the task content is; x +y = 0.

<h3>What is the restriction of the expression?</h3>

The expression in the task content is rational;

(1-x-y)/(x+y).

On this note, the restriction to the expression is the values which render the denominator of the expression equal to 0 and consequently the expression value to undefined.

Hence, the restriction is; x+y = 0.

Read more on undefined rational function;

brainly.com/question/8984184

#SPJ1

7 0

1 year ago

Allie has two cars- a truck and a sedan. Last week, she used 3 gallons of gas in the truck and 5 gallons of gas in the sedan and

gavmur [86]

Answer:

sedan = 26 miles/gallon

truck = 17 miles/gallon

Step-by-step explanation:

try to write the text in mathematical format as a system of equations

t=truck s=sedan

$\left \{ {{3t+5s=181} \atop {7t+6s=275}} \right.$

first equation can be written as

t= (181-5s)/3

we can use it in the second equation and rewrite it as

7[(181-5s)/3]+6s = 275

7(181/3 -5/3s) + 6s = 275

1267/3 - 35/3s + 6s = 275

-35/3s + 18/3s = 275-1267/3

-35/3s + 18/3s = 825/3 - 1267/3

-35s + 18s = 825 -1267

-17s = -442 s = 442/17 = 26 sedan has an average of 26 miles/gallon

we use this value of s in the first equation

3t + 5*26=181 3t=181-130 t= 51/3 = 17 truck has an average of 17 miles/gallon

5 0

3 years ago

The Delhi metro track is 240 \text{ km}240 km240, start text, space, k, m, end text long today. Two years ago, it was 200 \text{

madam [21]

Answer:

Step-by-step explanation:

4 0

2 years ago

Let f:a to b be a surjective map of sets prove that the relation a if and only if f(a) = f(b) is an equivalence relation whose e

MrRa [10]

Answer:

Step-by-step explanation:

Denote this equivalence relation by $"\sim"$ (i.e, $a\sim b$ if and only if $f(a)=f(b)$ ), is clear that $a\sim a$ is an equivalence relation since $"="$ is. Now, by definition we have that $[a]=\{b\sim a \mid f(a)=f(b) \}=f^{-1}(a)$ .