Answer:
D. x = 7
Step-by-step explanation:
NOTE : <u><em>there should be an equal sign somewhere in the given expression.</em></u>
suppose the equation is the following:
3(x-4)-5 = x-3
………………………………………………………
3(x - 4) - 5 = x - 3
⇔ 3x - 12 - 5 = x - 3
⇔ 3x - 17 = x - 3
⇔ 3x - 17 + 17= x - 3 + 17
⇔ 3x = x + 14
⇔ 2x = 14
⇔ x = 14/2
⇔ x = 7
Answer:
<em>The correct answer is: A</em>
Step-by-step explanation:
<u>Points on a Numeric Line</u>
The numeric line shown in the figure has four points A, B, C, and D. It's clear that each marked division of the line has a value of 1/4 units and all four points are below the reference zero, thus all are negative.
Point A is clearly on the -2 mark, thus
A=-2
Point B is one mark above A, thus it's located at:


Point C is one mark below -1, thus:

Finally, point D is one mark below 0:

The correct answer is: A
19? Lol........................
Given the equation - x² + 5x = 3, which can be rewritten as:
- x² + 5x - 3 = 0
where a = -1, b = 5 and c = -3.
Quadratic formula:
![\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7Bb%5E2%5Ctext%7B%20-%204ac%7D%7D%7D%7B2a%7D)
Now, we just replace the values of a, b and c on the equation above.
![\frac{-5\text{ }\pm\text{ }\sqrt[]{5^2\text{ - 4(-1)(3)}}}{2(-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B5%5E2%5Ctext%7B%20-%204%28-1%29%283%29%7D%7D%7D%7B2%28-1%29%7D)
=
Answer:
A) JK and AB =
So, =》
=》
[/tex]
B) AABC
So, 
C) AABM:
The value of k for which
is
ans[/tex]
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