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Papessa [141]
2 years ago
14

HELP QUICK PLEASE Determine the following values of the function. f(-3) = f(2) =

Mathematics
2 answers:
Tatiana [17]2 years ago
6 0
It says if x is less than or equal to 0 use 3x + 1
so -3 being less than 0, 3*-3 + 1 = -9 + 1 = -8
and if x is bigger or equal to 2, use 4
2 being equal to 2, you're value is 4
hence the answer for the funcion is -8 and 4
astra-53 [7]2 years ago
4 0
F(-3) would be -8, because you would use the first equation. f(2) would be 4 apparently cause theres no x after the 4, or in the equation of the 4. Hope this helps. Please rate, leave a thanks, and mark a brainliest answer(not necessarily mine). Thanks, it really helps! :D
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A florist sold 14 flower bouquets yesterday, including 7 lily bouquets. Based on past data, how many of the next 20 bouquets sol
tensa zangetsu [6.8K]

Answer:

10

Step-by-step explanation:

From past data:

Fraction of lily sold :

Total flowers / number of lily

Total flowers = 14

Number of lily = 7

Fraction of lily = 14 /7 = 1/2

Going by these ;

Expected number of lilies in the next 20 bouquets sold :

Fraction of lily * number of flower in bouquet

1/2 * 20

= 10 lilies

5 0
2 years ago
The answers x^1 or x^0<br> How??
pickupchik [31]
Remember a^(m) x a^(n) =  a(m+n) & √a = a^(1/2)


===> x^(1/2 -3/2)+x(1/2 -1/2) ====> x^(-1)+x^(0) (any number Exp 0 =1)
X^(-1) +1 ===> 1/x +1 or (1+x)/x


6 0
3 years ago
What is the domain of f/g, given f(x)=x+2 and g(x)=x-7?
kodGreya [7K]

Answer:

(-∞,7) U (7,∞)

Step-by-step explanation:

f(x)= x+2

g(x) = x-7

\frac{f(x)}{g(x)} =\frac{x+2}{x-7}

Here we have x-7 in the denominator

To find domain we set the denominator =0  and solve for x

x-7=0

Add 7 on both sides

x=7

x=7 makes the denominator 0 that is undefined

So we ignore 7 for x

Hence domain is

(-∞,7) U (7,∞)

5 0
2 years ago
Read 2 more answers
HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid
Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.




7 0
2 years ago
Read 2 more answers
ASAP
Virty [35]

Answer:a: y=4.5+0.75x

B: y=2.5+1.25x

C: 7.5

Step-by-step explanation:

6 0
3 years ago
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