Answer:
Bayes’ Theorem describes the probability of occurrence of an event related to any condition. It is also considered for the case of conditional probability.
For prove refer to the attachment.
Hope this helps you^_^
Integrating gives
To compute the integral, substitute 
, so that 
. Then
Since 
for all 
, we can drop the absolute value, so we end up with
Given that 
, we have
so that
Answer:
<em>Shayla charges $20 per hour for middle school students and $25 per hour for high school students.</em>
Step-by-step explanation:
<u>System of Equations</u>
Let's call:
x = Shayla's hourly charge for middle school students
y = Shayla's hourly charge for high school students
Last week, Shayla tutored middle school students for 5 hours and high school students for 12 hours. The total earning was 5x+12y. She earned $400 last week, thus:
5x + 12y = 400 [1]
This week, she tutored middle school students for 6 hours and high school students for 10 hours. The total earnings were 6x+10y and it represented $370, thus:
6x + 10y = 370
Dividing by 2:
3x + 5y = 185 [2]
We have formed the system of equations:
5x + 12y = 400 [1]
3x + 5y = 185 [2]
Multiply [1] by -3 and [2] by 5:
-15x - 36y = -1200
15x + 25y = 925
Adding both equations:
-11y = -275
Dividing by -11:
y = -275/(-11) = 25
y = 25
Substituting in [1]:
5x + 12*25 = 400
5x + 300 = 400
5x = 400 - 300 = 100
x = 100/5 = 20
x = 20
Shayla charges $20 per hour for middle school students and $25 per hour for high school students.
Answer:
Step-by-step explanation:
Hope this helps you
<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>
The answers for the question shown above are the option A, the option B and the option C, which are:
A.log5(15625)
<span> B.log5(5^6)
C.6
The explanation is shown below:
By applying the logarithms properties, you have:
A. </span><span>log5(125)+log5(125)=log5(125)(125)=log5(15625)
B. </span>log5(125)+log5(125)=log5(15625)=log5(5^6)
C. og5(125)+log5(125)=log5(15625)=log5(5^6)=6log5(5)=6
