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2 years ago

Find the value of p so the line that passes through (4, -2) and (p, -1) has a slope of negative 1/7

Mathematics

1 answer:

Colt1911 [192]2 years ago

6 0

Can u show what ur saying on a graph so i can solve it for u

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<img src="https://tex.z-dn.net/?f=8%20%2B%20y%20%3D%203y" id="TexFormula1" title="8 + y = 3y" alt="8 + y = 3y" align="absmiddle"

aksik [14]

Answer:

8 + y = 3y

8 = 3y - y

8 = 2y

8/2 = y

8 0

2 years ago

Read 2 more answers

The question is in the picture

GrogVix [38]

Ten-thousand AFAFANDIUAHDIUAHIUDHAIDh (had to write 20 more "letters")

8 0

2 years ago

A bank offers a loan for $8,000 which earns 4.25% interest compounded annually. What is the correct formula to determine how muc

Kisachek [45]

Answer:

C, A = 8,000(0.0425)5

7 0

2 years ago

Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a

labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute $e^{0.4}$ by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

$e^{0.4}$ < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$ , where $M=|F^{N+1}(x)|$

$\leq \frac{3}{(3+1)!} |-0.4|^4$

$\leq \frac{3}{24} \times (0.4)^4$

$\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0

2 years ago

An accident at an oil drilling platform is causing a circular oil slick. The slick is 0.07 foot thick, and when the radius of th

ololo11 [35]

Answer: $43.54 ft^3/min$

Step-by-step explanation:

Given

Thickness of oil slick=0.07 foot

radius of slick=110 ft

$\frac{\mathrm{d} r}{\mathrm{d} t}=0.9 ft/s$

Let V be the volume of oil slick

so, $V=0.07\pi \cdot r^2$

rate of oil flowing is

$\frac{\mathrm{d} V}{\mathrm{d} t}=0.07\times 2\pi \cdot r\frac{\mathrm{d} r}{\mathrm{d} t}$

$\frac{\mathrm{d} V}{\mathrm{d} t}=0.07\times 2\pi \times 110\times 0.9=43.54 ft^3/min$

7 0

2 years ago