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3 years ago

Find the value of p so the line that passes through (4, -2) and (p, -1) has a slope of negative 1/7

Mathematics

1 answer:

Colt1911 [192]3 years ago

6 0

Can u show what ur saying on a graph so i can solve it for u

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The angles in the diagram are supplementary.What is the measure of angle TSU? A.77 B . 63 C. 17 D . 9

lorasvet [3.4K]

Answer:

Step-by-step explanation:

supplementary angles =180 degrees

180-117=63

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2 years ago

Garrett works for a company that builds parking lots the graph shows the area of a parking lot based on the length of one side.

dedylja [7]

Answer: Option D.

Step-by-step explanation:

this is a quadratic equation of the form:

y = ax^2 + bx + c

First, things you must see.

The graph opens up, so we must have thata a is greater than zero, so we can discard the first option.

Second, we can see that the vertex is located in x ≈ 70

The vertex of a quadratic equation is: x = -b/2a

so we have:

70 = -b/2a

let's try our options and see if we can discard other:

-b/2a = 69.9/2 = 34.95

we can discard this option.

-b/2a = 78/2 = 39 we can discard this option.

-b/2a = 69.9/2*0.5 = 69.9

This is the only one that fits, so this is the correct option.

8 0

3 years ago

Someone answer this please

solniwko [45]

Answer:

D) -4(-1) > 2 is a true statement

Step-by-step explanation:

A) 3 < 0 False

B) -6 > -1 False

C) 0 < -4 False

3 0

3 years ago

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

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3 years ago

5d-7-d+4<br><br> pls help asap just solve it pls brainlest for the best

emmainna [20.7K]

Answer:

4d - 3

Is your simplified expression

5 0

3 years ago

Read 2 more answers