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3 years ago

NEED HELP ON THIS . THANKS FOR THE HELP

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

$\dfrac{1.4\cdot10^5}{3.5\cdot10^3}=\dfrac{1.4}{3.5}\cdot10^{5-3}=0.4\cdot10^2=0.4\cdot100=40$
The diameter of Jupiter is about 40 times the diameter of Earth's moon.

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The car dealership decides to revise its commission program. Now the salesperson gets a flat commission of $60 for every $200 of

DedPeter [7]

60 is what percent of 200...
60/200 = x/100
200x = 6000
x = 6000/200
x = 30%...that means for every sale, the sales person gets a 30% commission

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3 years ago

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andrezito [222]

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1 year ago

A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand

sesenic [268]

Answer:

The 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =80$ represent the sample mean 1

$\bar X_2 =75$ represent the sample mean 2

n1=25 represent the sample 1 size

n2=36 represent the sample 2 size

$\sigma_1 =5$ sample standard deviation for sample 1

$\sigma_2 =3$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =80-75=5$

Since the Confidence is 0.94 or 94%, the value of $\alpha=0.06$ and $\alpha/2 =0.03$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that $z_{\alpha/2}=1.88$

The standard error is given by the following formula:

$SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$

And replacing we have:

$SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118$

Confidence interval

Now we have everything in order to replace into formula (1):

$5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898$

$5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102$

So on this case the 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

7 0

3 years ago

Help plz I NEED IT Help help hjelp

DaniilM [7]

Answer:

Step-by-step explanation:

12 because that's how many dots/vertices are shown(sorry if im wrong)

6 0

2 years ago

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On Tuesday, Marissa was $45 short of her fundraising goal. The next day, she was $5 over her goal write an equation to show how

scoray [572]

Answer: Hello daema, let's let x be the goal and c be the collection per day.

x - 45 + c = x + 5 is the answer so now let's talk about how we did that.

So she wants to get to x which is the goal. But right now she has 45 less than what her goal is. So that would look like this x - 45 now she has to get c or the collection per day to get to her goal. So now it looks like this x - 45 + c. Now that c has to be at least x which is her goal, it now will look like this x - 45 + c = x. But we're not done, the question said that now she 5$ over her goal, or x. So we have to add the + 5 onto the end so now it looks like this x - 45 + c = x + 5. To solve the equation "if you have to" it would be x = 50$ per day.

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3 years ago